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Damm [24]
3 years ago
10

The _____ of an object is a measure of the distance an object moves in a given amount of time. *

Physics
1 answer:
DanielleElmas [232]3 years ago
7 0

Answer:

Option B) Speed is the answer.

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Maurice directs a beam of light on a sheet of glass at an angle of 51°. What is the angle of refraction in the glass? The refrac
iVinArrow [24]
Maurice directs a beam of light on a sheet of glass at an angle of 51°. The refractive index of glass is <span>1.46. </span>The angle of refraction in the glass is 29 degrees. The answer is letter B.
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2 years ago
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Wat would happen if a feather and a ball were released from the same height at the same time? Gravity Experiments for Kids – Sci
solniwko [45]

Answer:

They would land at the same time

Explanation:

They would land at the same exact time.

As weird, impossible and unbelievable as it appears. When in a vacuum, every weight, body and material when released from the same height would land on the ground at the same time. This also means that like in the question, a feather and a ball would land at the same time. And just for illustrations as well, a feather and a car would land at the same time as well.

6 0
3 years ago
A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s
DedPeter [7]

Answer:

212.8 m/s^{2}

Explanation:

Time taken by stone to cover horizontal distance

t=\sqrt{\frac {2h}{g}} where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

t=\sqrt{\frac {2*2.1}{9.81}}= 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

a=\frac {v^{2}}{r} where r is radius of circle, substituting r with 1.1m

a=\frac {15.3^{2}}{1.1}

a=212.8 m/s^{2}

Therefore, centripetal acceleration is 212.8 m/s^{2}

8 0
3 years ago
An object is accelerating at a constant rate due to a force being applied.what can be done to the force to decrease the objects
Sliva [168]

Answer:

y

Explanation:

W's your is kamiko ballsy go now cameco cicomaco C local cinema as he called summer cause she Laura she scola Kolyma see kamala cause he go see more across the ground come on I can I circular aggregate als the Irish Irish Irish

6 0
2 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
sammy [17]

Answer:

-0.25 rad/s^2

Explanation:

The equivalent of Newton's second law for rotational motions is:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

In this problem we have:

\tau = -12.5 Nm (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

I=50.0 kg m^2 is the moment of inertia

Solving for \alpha, we find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2

3 0
3 years ago
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