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mestny [16]
3 years ago
7

On the crossbuck or gate at the railroad crossing, there is a sign telling you how many tracks are at that crossing.

Physics
1 answer:
kogti [31]3 years ago
3 0
The cross buck signs have the words railroad and crossing in black and white assembled in a large x configuration. If there is more than one set of tracks this sign will tell how many tracks are there on a separate sign below the cross buck. As approach look and listen for an approaching train. The cross buck sign means the same as a yield sign which means that if a train is approaching you must yield and let the train pass. A recently enacted state law will require that a yield sign be placed below the cross buck sign at crossing that do not have stop signs or red flashing light signals. This is being done to further emphasize that a cross buck sign means that you must yield to trains.

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What is 3600Hz has in rpm?​
Setler [38]

Answer:

Explanation:

N=Rotor Speed in Revolution per minute(rpm)

for P=4 and N=3600, f comes out to be 120 Hz.

So frequency of voltage produced is 120 Hz. But this is not practical. Generally 4-Pole generator has N=1500rpm(for 50 Hz) or 1800rpm for 60 Hz. Two pole generator can have N=3600rpm(f=60Hz).

The most practical situation is generator having N=3600Hz with 2 Poles.

Hope It will be helpful!!!

8 0
3 years ago
What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s
AlexFokin [52]

Answer:

K=0.023J

Explanation:

From the question we are told that:

Mass m=0.15

Velocity v=0.5m/s

Angular Velocity \omega=8.4rad/s

Generally the equation for Kinetic Energy is mathematically given by

K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)

K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))

K=0.023J

8 0
2 years ago
Lol<br>idk what this is​
alex41 [277]

Answer:

I know

Explanation:

Physics= hard

3 0
3 years ago
Read 2 more answers
A skater of mass 40 kg is carrying a box of mass 5 kg. The skater has a speed of 5 m/s with respect to the floor and is gliding
Yuki888 [10]

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

p=mv

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

p=(5kg)(5m/s)\\p=25kg.m/s

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

p=(5kg)(5m/s)\\p=25kg.m/s

<em>It is the same that part a)</em>

8 0
3 years ago
Air is being blown into a spherical balloon at the rate of 1.68 in.3/s. Determine the rate at which the radius of the balloon is
NISA [10]

Answer: 0.006in/s

Explanation:

Let the rate at which air is being blown into a spherical balloon be dV/dt which is 1.68in³/s

Also let the rate at which the radius of the balloon is increasing be dr/dt

Given r = 4.7in and Π = 3.14

Applying the chain rule method

dV/dt = dV/dr × dr/dt

If the volume of the sphere is 4/3Πr³

V = 4/3Πr³

dV/dr = 4Πr²

If r = 4.7in

dV/dr = 4Π(4.7)²

dV/dr = 277.45in²

Therefore;

1.68 = 277.45 × dr/dt

dr/dt = 1.68/277.45

dr/dt = 0.006in/s

7 0
3 years ago
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