Hi hi I hope you know that you have a great time jaha
s = displacement; u = initial velocity; t = time of motion
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal, 
Time of flight :

Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Answer:
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