1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IrinaK [193]
3 years ago
5

A researcher testing the effects of two treatments for anxiety computed a 95% confidence interval for the difference between the

mean of treatment 1 and the mean of treatment 2. If this confidence interval includes the value of zero, then she should reject the null hypothesis that the two population means are equal: true or false?
Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

False

Step-by-step explanation:

Given that a researcher testing the effects of two treatments for anxiety computed a 95% confidence interval for the difference between the mean of treatment 1 and the mean of treatment 2

Also that  confidence interval includes zero.

When confidence interval includes zero, we need not reject the null hypothesis since null hypothesis claims that difference =0

When confidence interval includes 0 it confirms that there is no difference and hence null hypothesis should be accepted.

You might be interested in
Which expression is equivalent
NeTakaya

Answer:

the first one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is 83 divided with a remander
zysi [14]
41 and 1 remainder left
8 0
3 years ago
Read 2 more answers
Develop a 95% confidence interval for the expected value of y when x = 8. estimate the standard deviation of an individual value
zloy xaker [14]

I don’t know what the answer is I wish I could help

3 0
3 years ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
Can anyone help with this? I don't understand how to do this..
zubka84 [21]
1,029 cm2............
8 0
4 years ago
Other questions:
  • Find the missing segment in the attached image
    7·1 answer
  • Which expression is equivalent to −(4−3) ?
    11·2 answers
  • Please help me with number 6
    9·2 answers
  • Steve built a square hamster pen that has a perimeter of 240 centimeters What is the length of one side of Steve’s hamster pen?
    9·2 answers
  • (1)<br> (2)<br> 790<br> + 172<br><br><br> What is the answer
    10·1 answer
  • Which of the following situations represents a linear relationship?
    8·2 answers
  • No
    8·1 answer
  • A sector of a circle of 7cm has an area of 44cm².calculate the angle of the sector,correct to the nearest degree π =22\7​
    15·1 answer
  • Trong trường hợp nào giá bia sẽ tăng
    10·1 answer
  • What is the sum for 2x+10?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!