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kvasek [131]
2 years ago
5

Which of the following contain a delocalized pi bond... H2O, o3, HCN, CO3^2-

Chemistry
2 answers:
salantis [7]2 years ago
6 0

Answer : Option D) CO_{3}.

Explanation : A delocalized π bond are those π bonds in which the electrons are allowed to move freely over more than two nuclei. So, amongst the given molecules CO_{3} is the correct answer. As CO_{3} is a molecule which shares a π bond between one carbon and three oxygen atom. The electrons move freely over the whole molecule.

kumpel [21]2 years ago
4 0
You should remember that a pi bond is related to an alkene, compounds that have a double bond. Among the choices, the only compound that has a double bond is the CO3^2-. Since it is an ion, the pi electrons are delocalized, meaning, their location cannot be indicated as they rotate around the molecules. This is a result of following the octet rule.
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Marta_Voda [28]
I hope you are able to find your answer through the guidance of this site as I have yet to cover this topic in chemistry: http://scientifictutor.org/1021/chem-how-to-convert-between-grams-and-molecules/
7 0
3 years ago
How many grams of potassium (K) contain 5.11 x 10^22 atoms of potassium?
Darina [25.2K]

The atomic mass of K is 39

from Avogadro's law

39g of K contains 6.02x10^23 atoms

therefore if

39=6.02x19^23

X=5.11×10^22

making X the subject of the formula

X= (5.11×10^22×39)÷6.02×10^23

X= 33g

7 0
2 years ago
What are three similarities between biotic and abiotic factors?
Viktor [21]
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6 0
3 years ago
Please help me with this three questions
zheka24 [161]

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7 0
2 years ago
Ydrogen and fluorine combine according to the equation h2(g) + f2(g) → 2 hf(g) if 5.00 g of hydrogen gas are combined with 38.0
Alexxx [7]
<span> Molar mass (H2)=2*1.0=2.0 g/mol
Molar mass (F2)=2*19.0=38.0 g/mol
Molar mass (HF)=1.0+19.0=20.0 g/mol

5.00 g H2 * 1mol H2 /2 g H2=2.50 mol H2 
38.0 g F2*1mol F2/38.0 g F2=1.00 mol F2

                                   H2(g) + F2(g) → 2 HF(g)
From reaction        1 mol      1 mol
From problem      2.50 mol   1 .00mol

We can see that  excess of H2, and that F2 is a limiting reactant.
So, the amount of HF is limited by the amount of F2.

</span>                                 H2(g) + F2(g) → 2 HF(g)
From reaction                      1 mol       2  mol
From problem                      1.00 mol  2.00mol

2.00 mol HF can be formed.

2.00 mol HF*20.0g HF/1mol HF=40.0 g HF can be formed
4 0
3 years ago
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