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timurjin [86]
3 years ago
5

The reaction to prepare methanol from carbon monoxide and hydrogen ‍ is exothermic. If you wanted to use this reaction to produc

e methanol commercially, would high or low temperatures favor a maximum yield? Explain.
Chemistry
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

The reaction in low temperature will favor maximum yield.

Explanation:

Methanol is mainly produced by hydrogenation of carbon monoxide.It is the simplest alcohol which contain methyl group that is linked with hydroxyl group.Methanol is volatile,colorless,flammable liquid.

Ethanol is less toxic than methanol.Methanol is the precursor of acetic acid,methyl tertiary butyl ether.

During formation of commercial methanol,carbon dioxide and water acts as poisons to alkali metal methoxide catalyst in low temperature in methanol synthesis reaction.

More over,high temperature evaporates methanol.

You might be interested in
Baking soda, NaHCO3, can be commercially produced during a series of chemical reactions called the Solvay process. In this proce
Mnenie [13.5K]

Answer:

CaO(s) + 2NH4Cl(aq) -------> CaCl2(aq) + H2O(l) + 2NH3(g)

Explanation:

The solvay process is an important process in the chemical industry. In this process, ammonia gas is first dissolved in concentrated brine to form a mixture known as ammoniacal brine. This solution is made to trickle down the tower. A counter stream of carbon dioxide is forced up the tower. The two substances react to form sodium hydrogen trioxocarbonate IV. This substance is only slightly soluble and separates out as a solid sludge. The product is now dried and heated to give sodium trioxocarbonate IV.

The overall reaction of the process can be given as;

CaO(s) + 2NH4Cl(aq) -------> CaCl2(aq) + H2O(l) + 2NH3(g)

Calcium chloride is merely a by-product.

6 0
3 years ago
What state of matter change is rain?
Charra [1.4K]

Answer:

The state of matter of rain is liquid. Clouds are 2 states of matter, liquid and gas

Explanation:

5 0
3 years ago
Calculate the amount of gold deposited when a current of 5A is passed through a solution of gold salt for 2hrs 15mins. If the sa
Nataliya [291]

Answer:

a. 82.68 g b. 9.8 min

Explanation:

a. The amount of gold deposited by 5 A current in 2 hrs 15 mins

Since charge Q = It where I = current = 5 A and time = 2 hrs 15 mins = 2 × 60 min + 15 min = 120 + 15 min = 135 min = 135 × 60 s = 8100 s

Q = 5 A × 8100 s

= 40500 C

Also, Q = nF where n = number of moles of gold deposited and F = Faraday's constant = 96500 C

n = Q/F = 40500 C/96500 C = 0.4195 moles ≅ 0.42 mole

Now n = m/M where m = mass of gold and M = molar mass of gold = 197

m = nM

= 0.42 × 197 g

= 82.68 g

b. The time taken for 6g of gold to be deposited.

We first find the number of moles of gold in 6g of gold

Since n = m/M and m = 6 g

n = 6/197 = 0.0305 mole

Q = It = nF

t = nF/I

= 0.0305 mol × 96500 C/5 A

= 2939.09 mol C

= 587.82 s

Changing t to minutes

587.82/60 s = 9.8 min

8 0
3 years ago
Determine if the electron configurations are valid or invalid
Hunter-Best [27]

Answer:

1) A (valid)

2) B (Invalid)

3) B (Invalid)

4) A (valid)

5) B (Invalid)

6) B (Invalid)

Explanation:

Electronic configuration:

The electronic configuration is the arrangnment of electrons in orbitals (s, p, d, f, g, h so on) according to quantum  number and Aufbau rule.

An atom of element have orbitals, and electrons are revolving in it.

There are quantum numbers that describe the number of electron in specific shell.

The Principle quantum number is denoted by "n" and can not be "0".

These "n" is K, L, M, N and electrons are distribution in it.

K =2

L= 8

M= 18

According to Aufbau electron occupied in the lowest energy level before occupying the highest energy level.

According to this the electronic configuration is

1s², 2s², 2p⁶ and so on....

So,

"s" orbital accommodate maximum of 2 electrons

"p" orbital accommodate maximum of 6 electrons

"d" orbital accommodate maximum of 10 electrons

"f" orbital accommodate maximum of 14 electrons

and the coefficient 1, 2, 3, 4 are energy level of orbitals.

The 1st orbital is 1s and it only can occupy 2 electrons the next coming electron goes into 2s that also can occupy 2 electrons and the further electrons will go to 2p orbital.

So keeping in mind all above details we investigate all option one by one

1.  A (valid)

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵

This is valid option. number of electrons are rightly accommodated in orbitals. Also 3d is higher energy level than 4p.

______________

2.  B (Invalid)

1s², 2s², 2p⁶, 3s², 3p⁷

This is invalid option. number of electrons are not rightly accommodated in orbitals as "p" orbital can only accommodate 6 electrons and not more than 6.

________________

3.  B (Invalid)

[Xe], 7s², 6d¹, 5f⁸

This is Invalid option. Number of electrons are not rightly accommodated in orbitals. There should 5f orbital before 6d.

______________

4.  A (valid)

[Kr] 5s², 4d¹⁰, 5p⁵

This is valid option. number of electrons are rightly accommodated in orbitals.

______________

5.  B (Invalid)

[He]--

This is invalid option. There is no exact explanation of electron distribution in orbitals.

______________

6.  B (Invalid)

1s², 2s², 2p⁶, 3s³, 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s--

This is invalid option. number of electrons are not rightly accommodated in orbitals. As "s" can accommodate only 2 electrons not 3 electrons. also there is no details of 5s

______________

4 0
3 years ago
PLEASE HELP NOW!!!!!!!
Dahasolnce [82]
The  number of moles hydrogen produced when 6 moles of sodium are used is calculated  as below

2Na + 2H2O = 2NaOH  +H2

by use of mole ratio between Na to H2 which is 2:1 the moles of H2 is therefore

= 6 x1/2 = 3  moles of H2
7 0
3 years ago
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