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Salsk061 [2.6K]
4 years ago
13

Two masses move at right angles to each other and collide 1 mass is stopped what is the velocity of the other

Physics
1 answer:
slega [8]4 years ago
5 0

Let m1 and m2 be the two masses, whereby m1 is the one that stops upon collision (assuming an elastic collision). We use the conservation of the momentum for this situation, namely the total momentum of the two moving masses is conserved and equal the momentum of the mass2 after the collision:

m_1\overline{v_1}+m_2\overline{v_2}= m_2\overline{v}

From this we can determine the resulting velocity:

\overline{v} = \frac{m_1}{m_2}\overline{v_1}+\overline{v_2}

Which answers the question for general values of m1, m2, v1, and v2.

For instance, if m1=m2, and v1=v2=1 m/s then the resulting velocity of the mass2 would be sqrt(2) m/s in the direction of 45 degrees from its original path.

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8 0
3 years ago
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A 6.0-cm-diameter horizontal pipe gradually narrows to 4.5 cm. When water flows through this pipe at a certain rate, the gauge p
Rufina [12.5K]

Answer:

0.0072 m³/s

Explanation:

Using Bernoulli's law

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂ since the pipe is horizontal

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

flow rate is constant

A₁v₁ = A₂v₂

A₁ = πr₁² = π (0.06/2)² = 0.0028278 m²

A₂ = πr₂² = π (0.0225)² = 0.00159 m²

v₁  = (A₂ / A₁)v₂

v₁  = (0.00159 m²/ 0.0028278  m²) v₂ = 0.562  v₂

substitute v₁  into the Bernoulli's equation

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

500 ( 1 - 0.3161 ) v₂²  = (31.0 - 24 ) × 10³ Pa

341.924 v₂² = 7000

v₂² = 20.472

v₂ = √ 20.472 = 4.525 m/s

volume follow rate = 0.00159 m² ×  4.525 m/s = 0.0072 m³/s

8 0
3 years ago
What are two things that the amount of gravitational force between two object depends on
Amiraneli [1.4K]
1).  the product of the two masses being gravitationally attracted to each other

2).  the distance between their centers of mass

And that's IT.  The gravitational force between them depends on
only those two things, nothing else.
3 0
3 years ago
Read 2 more answers
Can anyone help? <br> Please and thank you
Juliette [100K]

Kinetic energy is calculated as such: KE=\frac{1}{2} mv^{2} | therefore, KE=0.913598 J

7 0
3 years ago
According to the law of conservation of matter, what number must be the same on each side of a chemical equation?
olga2289 [7]

Answer:

4. The number of atoms of each element

Explanation:

<em><u>Why is 1 wrong?</u></em>

The number of substances (i.e. number of mols of substances) do not have to be the same. For instance, 2 mol of water reacts with 1 mol of oxygen to form 2 mol of water. Obviously the numer of substances is not conserved. Thus, it isn't a requirement.

<em><u>Why is 2 wrong?</u></em>

The number of chemical symbols do not mean anything. They do not tell us anything about the quantity of matter, they only tell us about the elements that are involved in the reaction.

<em><u>Why is 3 wrong?</u></em>

Once again, the number of chemical formulas are meaningless.

<u><em>Why is 4 correct?</em></u>

The number of atoms are always conserved as atoms cannot be broken or created.

<em><u>Possible confusion...</u></em>

The number of atoms are always conserved but the number of molecules may not always be conserved.

Why? As 2 atoms may be a molecule on the reactant side and 4 atoms may become a molecule on the product size, causing the number of molecules to reduce by half, while the number of atoms remain constant.

Hope that makes sense!

7 0
3 years ago
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