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Nimfa-mama [501]
3 years ago
7

Be sure to answer all parts. Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everythi

ng from fats and waxes to airplane glue and nail polish. At high temperatures, it decomposes in a first-order process to methane and ethene (CH2═C═O). At 600°C, the rate constant is 8.7 × 10−3 s−1. (a) What is the half-life of the reaction
Chemistry
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

Half life = 79.67 sec

Explanation:

Given that:

k = 8.7\times 10^{-3}\ s^{-1}

The expression for half life is shown below as:-

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

t_{1/2}=\frac{\ln2}{8.7\times 10^{-3}\ s^{-1}}

t_{1/2}=114.94252\ln \left(2\right)\ sec=79.67\ sec

Half life = 79.67 sec

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Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance
ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

8 0
3 years ago
If you had a sample containing 55 alpha particles, how many protons would be present in that sample? Show all necessary work.
arlik [135]
An alpha particle is a helium nucleus without the electrons - 2 neutrons and 2 protons.

So, all you would have to do is 2 x 55, which equals 110.

8 0
3 years ago
Convert: 950 g to kg
scZoUnD [109]

Answer:your answer is 0.95

Explanation:

Because you put the number down if it is in the hundreds then put into a decimal that it is in the hundredths:)

4 0
3 years ago
The ionic equations represent the reactions between four metals, P, Q, R and S, and solutions of the salts of the same metals
EleoNora [17]

Answer:

P + Q2+ -> no reaction

R + P2+ -> R2+ + P

Q + S2+ -> Q2+ + S

S + P2+ -> S2+ + P

S + R2+ -> S2+ + R

S + Q2+ -> no reaction

What is the correct order of reactivity of the metals?

Most -----------------------> least

A. P R S Q

B. Q R S P

C. Q S R P

D. S Q P Rhhgu

5 0
3 years ago
You are given a silver rod, copper plate and copper sulphate solution. Explain the arrangements you will do to get coating of co
Mandarinka [93]

<u>U</u> <u>VORBELLO</u> <u>FRANÇAIS</u><u>?</u><u>?</u><u>?</u>

6 0
3 years ago
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