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Nimfa-mama [501]
3 years ago
7

Be sure to answer all parts. Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everythi

ng from fats and waxes to airplane glue and nail polish. At high temperatures, it decomposes in a first-order process to methane and ethene (CH2═C═O). At 600°C, the rate constant is 8.7 × 10−3 s−1. (a) What is the half-life of the reaction
Chemistry
1 answer:
Kazeer [188]3 years ago
6 0

Answer:

Half life = 79.67 sec

Explanation:

Given that:

k = 8.7\times 10^{-3}\ s^{-1}

The expression for half life is shown below as:-

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

t_{1/2}=\frac{\ln2}{8.7\times 10^{-3}\ s^{-1}}

t_{1/2}=114.94252\ln \left(2\right)\ sec=79.67\ sec

Half life = 79.67 sec

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Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be
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Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

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Limiting reactant = ?

Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

                160 g of CuSO₄  ----------------- 1 mol

                156 g                   -----------------  x

                      x = (156 x 1) / 160

                      x = 0.975 moles

               27 g of Al -------------------------- 1 mol

               29 g of Al -------------------------- x

                x = (29 x 1)/27

                x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical     3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental  0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.      

                    3 moles of CuSO₄ ------------------ 3 moles of Cu

                 0.975 moles of CuSO₄ ---------------  x

                         x = (0.975 x 3)/3

                        x = 0.975 moles of Cu were obtained.        

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