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topjm [15]
1 year ago
14

A buffer is prepared by adding 300. 0 ml of 2. 0 mnaoh to 500. 0 ml of 2. 0 mch3cooh. what is the ph of this buffer? ka= 1. 8 10

-5(ans. 4. 92)
Chemistry
1 answer:
Anton [14]1 year ago
6 0

The Henderson-Hasselbalch equation can be used to determine the pH of the buffer from the pKa value. The pH of the buffer will be 4.75.

<h3>What is the Henderson-Hasselbalch equation?</h3>

Henderson-Hasselbalch equation is used to determine the value of pH of the buffer with the help of the acid disassociation constant.

Given,

Acid disassociation constant (ka) = 1. 8 10⁻⁵

Concentration of NaOH = 2.0 M

Concentration of CH₃COOH = 2.0 M

pKa value is calculated as,

pKa = -log Ka

pKa = - log (1. 8 x 10⁻⁵)

Substituting the value of pKa in the Henderson-Hasselbalch equation as

pH = - log (1. 8 x 10⁻⁵) + log [2.0] ÷ [2.0]

pH = - log (1. 8 x 10⁻⁵) + log [1]

= 4.745 + 0

= 4.75

Therefore, 4.75 is the pH of the buffer.

Learn more about the Henderson-Hasselbalch equation here:

brainly.com/question/27751586

#SPJ4

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Answer:

2.67 × 10⁻²

Explanation:

Equation for the reaction is expressed as:

CaCrO₄(s)    ⇄      Ca₂⁺(aq)         +        CrO₂⁻⁴(aq)

Given that:

Kc=7.1×10⁻⁴

Kc= [Ca^{2+}][CrO^{2-}_4]

Kc= [x][x]

Kc= [x²]

7.1×10⁻⁴ =  [x²]

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How many moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 ATM
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Answer:

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= 200.8 atm
  • V= 35 L
  • n=?
  • R= 0.082 \frac{atm*L}{mol* K}
  • T= 27.3 C= 300.3 K (being O C= 273 K)

Replacing:

200.8 atm* 35 L= n* 0.082\frac{atm*L}{mol* K} * 300.3 K

Solving:

n=\frac{200.8 atm* 35 L}{0.082\frac{atm*L}{mol* K} * 300.3 K}

n= 285.4 moles

<u><em>285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.</em></u>

<u><em></em></u>

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