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pentagon [3]
3 years ago
10

Two point charges Q1 = +4.10 nC and Q2 = −2.40 nC are separated by 55.0 cm. (a) What is the electric potential at a point midway

between the charges? 55.57 Correct: Your answer is correct. seenKey 55.6 V (b) What is the potential energy of the pair of charges? -1.61E-7 Correct: Your answer is correct. seenKey -1.61e-07 J What is the significance of the algebraic sign of your answer? correct Positive work must be done to separate the charges. Negative work must be done to separate the charges. Correct: Your answer is correct.
Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

A) V = 55.57 V

B) E = -1.61 x 10^(-7)J

C) Negative sign means that positive work must be done to separate the charges (bring them up to a state of zero potential energy)

Explanation:

A) Electric potential is given by the formula;

V = KQ/d

Since there are two charges and we are looking for the electric potential at a point midway through them, we now have;

V = kQ1/0.5d + kQ2/0.5d

This can be arranged as;

V = (k/0.5d)(Q1 + Q2)

Where;

k is coulombs constant and has a value of 8.99 x 10^(9) N.m²/C²

d = 55 cm = 0.55m

Q1 = +4.10 nC = 4.1 x 10^(-9) C

Q2 = −2.40 nC = -2.4 x 10^(-9) C

Thus;

V = (8.99 x 10^(9))/(0.5 x 0.55)[4.1 x 10^(-9) - 2.4 x 10^(-9)]

V = 55.57 V

B) The formula for the potential energy of the pair of charges is;

E = kQ1•Q2/d

Thus, E = [(8.99 x 10^(9)) * 4.1 x 10^(-9) * -2.4 x 10^(-9)]/0.55

E = -160.8 x 10^(-9)

Or

E = -1.61 x 10^(-7)J

C) Negative sign means that positive work must be done to separate the charges (bring them up to a state of zero potential energy)

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La altura de un tornillo de banco respecto a la superficie es de 80 cm expresar dicha medida en pies..
Andrej [43]

Answer:

this measurement if feet is: 2.624672 ft

Explanation:

Notice that 80 cm can be expressed as 0.8 meters, and In order to convert from meters to feet, one needs to multiply the meter measurement times 3.28084. Therefore:

0.80 m can be written in feet as: 0.80 * 3.28084 feet = 2.624672 feet

3 0
2 years ago
A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?
Agata [3.3K]

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book  = 1.15kg

Unknown:

Magnitude of the normal force  = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

 Normal force  = mass x acceleration due to gravity

 Normal force  = 1.15 x 9.8  = 11.27N

5 0
2 years ago
I need help with this
ra1l [238]

What is that?? Please tell us

5 0
3 years ago
A bolt of lightning discharges 9.7 C in 8.9 x 10^-5 s. What is the average current during the discharge?
Anastaziya [24]

Answer: 1.089\times 10^5\ A

Explanation:

Given

Charge discharged Q=9.7\C

time taken t=8.9\times 10^{-5}\ s

Current is given as rate of change of discharge i.e.

\Rightarrow I=\dfrac{Q}{t}\\\\\Rightarrow I=\dfrac{9.7}{8.9\times 10^{-5}}\\\\\Rightarrow I=1.089\times 10^5\ A

Therefore, the average current is 1.089\times 10^5\ A

3 0
2 years ago
A cow wanders 30 m North, turns 22 degrees right of its original path, and wanders another 40 m. Find its total displacement.
scoundrel [369]

Answer:OB=58.3m

Explanation:

So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.

now take the starting point as a origin such that cow moves in x-y co-ordinate axis.

As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.

So the final displacement is the length of cow from the origin that is length OB.

now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]

now displacement of cow= length of OB

                                           = \sqrt{[37.084]^{2}+[44.984]^{2}  }

                                           =\sqrt{3398.78}

                                     OB =58.3

                                         

7 0
9 months ago
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