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katovenus [111]
3 years ago
14

A hot-air balloon is ascending at the rate of 12 m/s and is 80 m above the ground when a package is dropped over the side. (a) H

ow long does the package take to reach the ground? (b) With what speed does it hit the ground?
Physics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

Explanation:

Given

balloon is ascending at the rate of u=12\ m/s

Balloon is at a height of s=80\ m

As the package is dropped from the balloon it must possess the same initial velocity as the balloon

using

v^2-u^2=2as  

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2=12^2+2\times 9.8\times 80

v^2=1712

v=41.37\ m/s

time taken is  given by

v=u+at

substituting values

41.37=-12+9.8\times t

as we consider downward direction as positive

t=\frac{53.37}{9.8}

t=5.44\ s

therefore time taken to reach the bottom is t=5.44 s                                            

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