Answer:
COMPLETE QUESTION
A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?
Explanation:
Given that,
Extension of spring
x = 0.0208m
Mass attached m = 3.39kg
Additional mass to have a frequency f
Let the additional mass be m
Using Hooke's law
F= kx
Where F = W = mg = 3.39 ×9.81
F = 33.26N
Then,
F = kx
k = F/x
k = 33.26/0.0208
k = 1598.84 N/m
The frequency is given as
f = ½π√k/m
Make m subject of formula
f² = ¼π² •(k/m
4π²f² = k/m
Then, m4π²f² = k
So, m = k/(4π²f²)
So, this is the general formula,
Then let use the frequency above
f = 3Hz
m = 1598.84/(4×π²×3²)
m = 4.5 kg
The International System Units or the SI units is scientific method of expressing the magnitudes or quantities of important natural phenomena. There are seven base units in the system, from which other units are derived. This system was formerly called the meter-kilogram-second (MKS) system.
True IF the engine is 25% efficient. False otherwise.
Answer:
Going from earth to the sun a probe would encounter the next layers in order:
- Corona
- Transition Region
- Chromosphere
- Photosphere
- Convection Zone
- Radiative Zone
- Core
A brief description of them:
Corona is the outermost layer and it cannot be seen with the naked eye, is starts at about 2100 km from the surface of the sun and it has no limit defined.
Transition Region is between the corona and the chromosphere, it has an extension of about 100km
The chromosphere is between 400 km from the surface of the sun to 2100 km. In this layer the further you get away from the sun it gets hotter.
The photosphere is the surface of the sun, the part that we can see, and extends from the surface to 400km.
The convection zone is where convection happens, hot gas rises, cools and rises again.
Radiative Zone is where the photons try to rise to move to higher layers.
The core of the Sun is where nuclear fusion occurs due to the very high temperatures.
Explanation:
We want to find the statement that is proven by the fact that the balls reach the same height.
A isn't supported by the evidence. Balls can reach the same height without having the same initial speed.
B isn't supported by the evidence. Balls can reach the same height without having the same launch angle.
C is supported. Projectiles spend the same amount of time going up as they do coming down, so if two projectiles reach the same height, then they must spend the same amount of time in the air.
D isn't supported by the evidence. Balls thrown at the same speed and complementary angles have the same range but different heights.
E isn't supported by the evidence. The mass of the ball doesn't affect the height.