Only one of the following is possible for a moving object. Which one? The velocity is directed eastward and is decreasing, while
1 answer:
Answer:
The velocity is zero at one instant, and the acceleration is not zero at that instant.
Explanation:
We know that
Where
a is the acceleration of moving object
V is the velocity.
When velocity of object is increasing with time then it means that object is accelerated.
When velocity of object is decreasing with time then it means that object is de-accelerated.
When velocity is constant it means that acceleration of object is zero.
So at particular position the instant velocity of block is zero but acceleration is not zero at that instant.
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Answer:
The thrown rock strike 2.42 seconds earlier.
Explanation:
This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:
So now we have an equation and unkown value.
for the thrown rock
for the dropped rock
solving both equation with the quadratic formula:
we have:
the thrown rock arrives on t=5.4 sec
the dropped rock arrives on t=7.82 sec
so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)
Answer:
least distance= 13mm
ratio of the lattice = 1 : 0.71 : 0.58
Explanation:
given λ₁ = 650nm = 650×10⁻⁹m, λ₂ = 500nm = 500×10⁻⁹m
