Answer:
s₁ = 0.022 m
Explanation:
From the law of conservation of momentum:
where,
m₁ = mass of hockey player = 97 kg
m₂ = mass of puck = 0.15 kg
u₁ = u₂ = initial velocities of puck and player = 0 m/s
v₁ = velocity of player after collision = ?
v₂ = velocity of puck after hitting = 48 m/s
Therefore,
negative sign here shows the opposite direction.
Now, we calculate the time taken by puck to move 14.5 m:
Now, the distance covered by the player in this time will be:
<u>s₁ = 0.022 m</u>
Answer:
3658.24m
Explanation:
Hello!
the first thing that we must be clear about is that the train moves with constant acceleration
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf = final speed =160km/h=44.4m/s
Vo = Initial speed =42.9km/h=11.92m/s
A = acceleration =0.25m/s^2
X = displacement
solving
the distance traveled by the train is 3658.24m
Answer:
75m/s
Explanation:
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