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Nimfa-mama [501]
4 years ago
11

Which part of an atom is responsiblefon the flow of electricity?*​

Physics
1 answer:
svlad2 [7]4 years ago
3 0

Answer:

The Electron

Explanation:

Electrons are how some atoms let electricity flow easily. If have closely bound electrons, then they are a bad conductor, or insulator. Atoms with loosely bound electrons allow electricity to easily flow, making these types of atoms great conductors. This is the case with most metals, where their electrons are very loose, making metals, like copper, great at transmitting electricity.

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A ski resort consists of a few chairlifts and several interconnected downhill runs on the side of a mountain, with a lodge at th
Aleks04 [339]
  1. A sketch of the junction between one chairlift and two runs is shown in the image attached below.
  2. For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

<h3>What is Kirchhoff's loop rule?</h3>

Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.

<h3>How to connect two runs in series?</h3>

Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.

For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

Read more on Kirchhoff's loop rule here: brainly.com/question/15003023

#SPJ4

7 0
1 year ago
Consider an ideal monatomic gas of N particles with mass m in thermal equilibrium at a temperature T. The gas is contained in a
harina [27]

Answer:

K.E.=\dfrac{3}{2}KT

Explanation:

Given that

Number of particle =N

Equilibrium temperature= T

Side of cube = L

Gravitational acceleration =g

The kinetic energy of an atom  given as

K.E.=\dfrac{3}{2}KT

Where

Equilibrium temperature= T

Boltzmann constant =K

        K =1.380649×10−23 J/K

3 0
3 years ago
Which of these chemical compounds is generated during the process of cellular respiration
Mariulka [41]

"Cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water." ~https://www.britannica.com/science/cellular-respiration


8 0
4 years ago
Read 2 more answers
1
Jet001 [13]

Answer:

the answer is C

Explanation:

you said its c

5 0
3 years ago
Read 2 more answers
A two-resistor voltage divider employing a 2-k? and a 3-k? resistor is connected to a 5-V ground-referenced power supply to prov
vesna_86 [32]

Answer:

circuit sketched in first attached image.

Second attached image is for calculating the equivalent output resistance

Explanation:

For calculating the output voltage with regarding the first image.

Vout = Vin \frac{R_{2}}{R_{2}+R_{1}}

Vout = 5 \frac{2000}{5000}[/[tex][tex]Vout = 5 \frac{2000}{5000}\\Vout = 5 \frac{2}{5} = 2 V

For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.

so.

R_{out} = R_{2} || R_{1}\\R_{out} = 2000||3000 = \frac{2000*3000}{2000+3000} = 1200

Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.  

if the -5% is applied to both resistors the Voltage is still 5V because the quotient  has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:

Vout = 5 \frac{1900}{4900}\\Vout = 5 \frac{19}{49} = 1.93 V

Vout = 5 \frac{2100}{5100}\\Vout = 5 \frac{21}{51} = 2.05 V

R_{out} = R_{2} || R_{1}\\R_{out} = 1900||2850= \frac{1900*2850}{1900+2850} = 1140

R_{out} = R_{2} || R_{1}\\R_{out} = 2100||3150 = \frac{2100*3150 }{2100+3150 } = 1260

so.

V_{out} = {1.93,2.05}V\\R_{1} = {1900,2100}\\R_{2} = {2850,3150}\\R_{out} = {1140,1260}

4 0
3 years ago
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