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Nimfa-mama [501]
3 years ago
11

Which part of an atom is responsiblefon the flow of electricity?*​

Physics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

The Electron

Explanation:

Electrons are how some atoms let electricity flow easily. If have closely bound electrons, then they are a bad conductor, or insulator. Atoms with loosely bound electrons allow electricity to easily flow, making these types of atoms great conductors. This is the case with most metals, where their electrons are very loose, making metals, like copper, great at transmitting electricity.

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A ball is swung in a horizontal circle at a constant speed. Each circle takes 0.85 seconds to complete and the rope is 0.40 m lo
BaLLatris [955]

Answer:

The centripetal acceleration will be "21.785 m/s²".

Explanation:

The given values are:

Time,

t = 0.85 seconds

Length of rope,

r = 0.40 m

Mass of ball,

m = 0.80 kg

As we know,

⇒ w=\frac{2 \pi}{t}

On substituting the values, we get

⇒      =\frac{2\times 3.14}{0.85}

⇒      = \frac{6.28}{0.85}

⇒      =7.38 \ rad/s^2

The centripetal acceleration will be:

⇒  a=r\times w^2

⇒     =0.40\times (7.38)^2

⇒     =0.40\times 54.46

⇒     =21.785 \ m/s^2

7 0
2 years ago
Two mirrors are at right angles to one another. A light ray is incident on the first at an angle of 30° with respect to the norm
marta [7]

Answer:

reflected angle - secod mirror = 60°

Explanation:

I attached an image with the solution to this problem below.

In the solution the reflection law, incident angle = reflected angle, is used. Furthermore some trigonometric relation is used.

You can notice in the image that the angle of reflection in the second mirror is 60°

7 0
3 years ago
Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

3 0
3 years ago
Why is it important to consider the experimental error in all the empirical results presented?
irinina [24]

Answer:

It is very important because scientists, especially the ones with empirical experiments and results, are prone to error and the empirical data is in need to be under strict observation done not only by many scientists but also by expermiented ones. This guards everybody to change the parameters suddenly which can affect the real results of an experiment 

Explanation:

6 0
3 years ago
Read 2 more answers
I am trying to find the magnitude of a resultant vector. Do i take inconsideration the negatives when i find the x & y compo
attashe74 [19]
Absolutely !  If you have two vectors with equal magnitudes and opposite
directions, then one of them is the negative of the other.  Their correct
vector sum is zero, and that's exactly the magnitude of the resultant vector.

(Think of fifty football players pulling on each end of the rope in a tug-of-war. 
Their forces are equal in magnitude but opposite in sign, and the flag that
hangs from the middle of the rope goes nowhere, because the resultant
force on it is zero.)

This gross, messy explanation is completely applicable when you're totaling up
the x-components or the y-components.
4 0
3 years ago
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