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3 years ago

What must happen for liquid water to become water vapor?

Physics

2 answers:

motikmotik3 years ago

8 0

The water molecules must gain kinetic energy in order to become water vapour

il63 [147K]3 years ago

6 0

Answer:

<h2>C. The water molecules must gain kinetic energy.</h2>

Explanation:

When liquid water become water vapor, molecules move more, because they force between them is less strong. Notice that vapor water as lower consistency, it's like smoke where molecules can way anywhere, at this stage the force between molecules is not strong enough to maintain a ridig shape.

Now, at vapor stage, molecues have to gain more kinetic energy, because the least is the force between molecules, the more kinetic energy is gonna there.

Therefore, the right answer is C.

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1 year ago

Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through

Norma-Jean [14]

Answer:

1. $\theta=29.84^{0}$

2. $\theta=60.15^{0}$

Explanation:

Polarizes axis can create two possible angles with the vertical.

first we have to find the intensity of first polarizer

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$I=\frac{I_{0} }{2}$

$I= \frac{655\frac{W}{M^{2} } }{2}$

$I=327.5\frac{W}{m^{2} }$

For a smaller angle for the first polarizer:

According to Malus Law

$I_{2} =I_{1} Cos^{2}(90^{0} - \theta)$

$I_{2} =I_{1} sin^{2}\theta$

$\frac{I_{2} }{I_{1} }=Sin^{2}\theta$

taking square root on both sides

$\sqrt{\frac{163}{327.5} } = sin\theta$

$\theta=Sin^{-1}(0.4977)$

$\theta=29.84^{0}$

For a larger angle for the first polarizer:

According to Malus Law

$I_{2} =I_{1} cos^{2}\theta$

$\frac{I_{2} }{I_{1} }=Cos^{2}\theta$

taking square root on both sides

$\sqrt{\frac{163}{327.5} } = cos\theta$

$\theta=Cos^{-1}(0.4977)$

$\theta=60.15^{0}$

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