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sleet_krkn [62]
3 years ago
9

HELP ME ILL GIVE BRAINLIST ​(please explain how to do it)

Physics
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

I honestly don't know(sorry)

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Exercising at a level thats beyond your regular daily activities is
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Healthy to get better at your daily activities but harmful to your body if you overdo it
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4 years ago
In a lab, a 5 L sample of gas with a pressure of 6 atm was transferred to a one liter flask.
wolverine [178]

Answer:

30 atm

Explanation:

P1V1 = P2V2

P2 = P1V1/V2

P2 = (6 atm * 5 L) / 1L

P2= 30 atm

6 0
3 years ago
What is Newton's law of universal gravitation?
pshichka [43]
Newton's law of universal gravitation<span> states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. hope this helps =)</span>
8 0
3 years ago
Read 2 more answers
A physicist performing a sensitive measurement wants to limit the magnetic force on a moving charge in her equipment to less tha
lawyer [7]

Answer:

Maximum charge will be 6.66\times 10^{-9}C

Explanation:

We have given force ion the moving charge F=10^{-12}N

Maximum speed of the moving charge v = 30 m /sec

Magnetic field B=5\times 10^{-5}T

We have to fond the charge

Force on moving charge is given by

F=qvB

So 10^{-12}=q\times 30\times 5\times 10^{-5}

q=6.66\times 10^{-9}C

Maximum charge will be 6.66\times 10^{-9}C

5 0
4 years ago
Find the kinetic energy ofan electron that moves at half the speed of light to four significant digits.
Vlad1618 [11]

Answer:

Ke=electron kinetic energy=10.24*10^{33} J

Explanation:

The electron has a mass of 9.1*10^{-31} kg

The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to 3*10^{8} \frac{m}{s}

Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

K=\frac{1}{2} *m*v^{2}        Equation(1)

K=kinetic energy (J)

m =mass of the body (kg)

v= speed of the body(\frac{m}{s} )

for this problem We replace in the equation (1)

me=9.1*10^{-31} kg = electron mass

ve=1.5*10^{8} \frac{m}{s}=Half the speed of light

=electron speed

We replace in  the  equation (1) :

Ke=\frac{1}{2}*me*ve^{2}

Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}

Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}

Ke=10.24*10^{33} J

The energy kinetic of the electron is 10.24*10^{33} Joules

7 0
3 years ago
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