1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
77julia77 [94]
3 years ago
9

Consider three drinking glasses. All three have thesame area base, and all three are filled to the same depth withwater. Glass A

is cylindrical. Glass B is wider at the top than atthe bottom, and so holds more water than A. Glass C is narrower atthe top than at the bottom, and so holds less water than A. Whichglass has the greatest liquid pressure at the bottom?
a. Glass A
b. Glass B
c. Glass C
d. All three have equal non-zero pressure at the bottom.
e. All three have zero pressure at the bottom.
Physics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

The correct answer is C.  All three have equal non-zero pressure

Explanation:

Pressure is the relationship between the force and the area of ​​a body, when the bodies are liquid the formula that

         P = rho g h

Where rho is the density and h the height of the liquid

We see that for this expression the pressure does not depend on the shape of the container, but on its height, as the three vessels have the same height, the pressure at the bottom is the same.

The correct answer is C   All three have equal non-zero pressure

You might be interested in
A girl of mass m1=60 kilograms springs from a trampoline with an initial upward velocity of v1=8.0 meters per second. At height
AleksandrR [38]

a) 5.0 m/s

This first part of the problem can be solved by using the conservation of energy. In fact, the mechanical energy of the girl just after she jumps is equal to her kinetic energy:

E_i=\frac{1}{2}m_1v_1^2

where m1 = 60 kg is the girl's mass and v1 = 8.0 m/s is her initial velocity.

When she reaches the height of h = 2.0 m, her mechanical energy is sum of kinetic energy and potential energy:

E_f = \frac{1}{2}m_1 v_2 ^2 + m_1 gh

where v2 is the new speed of the girl (before grabbing the box), and h = 2.0m. Equalizing the two equations (because the mechanical energy is conserved), we find

\frac{1}{2}m_1 v_1^2 = \frac{1}{2}m_1 v_2 ^2 + m_1 gh\\v_1^2 = v_2^2 +2gh\\v_2 = \sqrt{v_1^2 -2gh}=\sqrt{(8.0 m/s)^2-(2)(9.8 m/s^2)(2.0 m)}=5.0 m/s

b) 4.0 m/s

After the girl grab the box, the total momentum of the system must be conserved. This means that the initial momentum of the girl must be equal to the total momentum of the girl+box after the girl catches the box:

p_i = p_f\\m_1 v_2 = (m_1 + m_2) v_3

where m2 = 15 kg is the mass of the box. Solving the equation for v3, the combined velocity of the girl+box, we find

v_3 = \frac{m_1 v_2}{m_1 + m_2}=\frac{(60 kg)(5.0 m/s)}{60 kg+15 kg}=4 m/s

c) 2.8 m

We can use again the law of conservation of energy. The total mechanical energy of the girl after she catches the box is sum of kinetic energy and potential energy:

E_i = \frac{1}{2}(m_1+m_2) v_3^2 + (m_1+m_2)gh=\frac{1}{2}(75 kg)(4 m/s)^2+(75 kg)(9.8 m/s^2)(2.0m)=2070 J

While at the maximum height, the speed is zero, so all the mechanical energy is just potential energy:

E_f = (m_1 +m_2)gh_{max}

where h_max is the maximum height. Equalizing the two expressions (because the mechanical energy must be conserved) and solving for h_max, we find

E_i = (m_1+m_2)gh_{max}\\h_{max}=\frac{E_i}{(m_1+m_2)g}=\frac{2070 J}{(75 kg)(9.8 m/s^2)}=2.8 m

4 0
3 years ago
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
  • During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
  • The equilibrium condition will be reached when the following equation be met:

       \Delta Q = c_{st}* m_{A} * (T_{fin}  - T_{0A} ) = c_{st}* m_{B} * (T_{0B}  - T_{fin} )

  • Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for  Tfin, as follows:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
  • When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
  • So, option b) is the right one.
8 0
3 years ago
Based on the data in the table...especially the provided melting points, which two substances are
ArbitrLikvidat [17]

The two substances that are mostly likely examples of covalent bonding are Sucrose and Ethanol.

<h3 /><h3 /><h3>What is a covalent Bond?</h3>
  • A covalent bond is a type of chemical bond that involves the sharing of pairs of electron between atoms.

Examples of compounds with covalent bond include the following;

  • Distilled water
  • Sucrose
  • Ethanol

Olive oil is a mixture not a compound

Sodium Chloride & Potassium lodide are examples of ionic bond.

Thus, the two substances that are mostly likely examples of covalent bonding are Sucrose and Ethanol.

Learn more about covalent bonds here: brainly.com/question/12732708

7 0
2 years ago
Hello,help me with this out please i need it hurry but please ensure your answer is correct..I attach here with my question.
lilavasa [31]

Answer:

.409 N

Explanation:

For this to balance, the moments around the fulcrum must sum to zero.

On the left you have   .21   ( is that down? I will assume it is)

      Counterclockwise moments :

        .21 * 40     +  1.0 * 20    

     Clockwise moments :

        .5 * 20     +     F * 45

these moments must equal each other

.21*40 + 1 *20   =  .5 * 20 + F * 45

   F = .409 N

7 0
2 years ago
It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass
vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

v^{2}=u^{2}+2\cdot a \cdot s

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/Sec^{2}

s= Distance traveled before stop m

Case 1

u=  13 m/sec, v=0, s= 57.46 m, a=?

0^{2} = 13^{2}  + 2 \cdot a \cdot57.46

a = -1.47 m/Sec^{2} (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/Sec^{2} (since same friction force is applied)

v^{2} = 29^{2}  - 2 \cdot 1.47 \cdot S

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

4 0
2 years ago
Other questions:
  • A person pours 330 g of water at 55°C into an 855-g aluminum container with an initial temperature of 10°C. The specific heat of
    14·1 answer
  • A basketball weighting 0.5kg is flying through the air at 10m/s. what is the kinetic energy
    14·1 answer
  • Which statement is true about air pressure acting in an object
    13·1 answer
  • What is the name of a 3D object I should be afraid of
    8·1 answer
  • A car traveling at 40 ft/sec decelerates at a constant 5 feet per second per second. how many feet does the car travel before co
    15·1 answer
  • Which two factors does the power of a machine depend on?
    9·1 answer
  • A wave travels through a medium and displaces the particles perpendicular to the direction in which the wave is traveling. This
    10·2 answers
  • On Friday, September 28, 2018, Palu, Indonesia, on the island of Sulawesi, experienced an earthquake that generated a tsunami. F
    10·1 answer
  • An airplane crooses the United States from San Francisco to Boston in 4 hours 20 min. Find the average speed if the distance is
    8·1 answer
  • jonatha want to put ketchup o​​​​​n his hamburger.he truns the ketchup bottle at an angle toward his plate and smacks the bottom
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!