Answer:
Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².
Explanation:
The period (T) of a spring in oscillation = 2π √(m/k)............. equation 1
Where m = mass acting on the spring (kg), k = spring constant of the spring (kg/s²).
Making k the subject of equation 1
k = T²/(4π²×m) .......................... equation 2
From the question, F = 4.42 Hz,
since T = 1/F
then, T = 1/F = 1/4.42 =0.226 s, π = 3.143
since the weight of the mass is evenly distributed over the four identical spring, Hence
m = 1450/4 = 362.5 kg
Substituting these values into equation 2
k = 0.226/{(4×3.143²)362.5}
k = 0.226/(14323.751)
k = 0.0000016 kg/s²
k = 1.6 × 10⁻⁶ kg/s².
Therefore, the spring constant of each spring = 1.6 × 10⁻⁶ kg/s².
Given Information:
Frequency of horn = f₀ = 440 Hz
Speed of sound = v = 330 m/s
Speed of bus = v₀ = 20 m/s
Answer:
Case 1. When the bus is crossing the student = 440 Hz
Case 2. When the bus is approaching the student = 414.9 Hz
Case 3. When the bus is moving away from the student = 468.4 Hz
Explanation:
There are 3 cases in this scenario:
Case 1. When the bus is crossing the student
Case 2. When the bus is approaching the student
Case 3. When the bus is moving away from the student
Let us explore each case:
Case 1. When the bus is crossing the student:
Student will hear the same frequency emitted by the horn that is 440 Hz.
f = 440 Hz
Case 2. When the bus is approaching the student
f = f₀ ( v / v+v₀ )
f = 440 ( 330/ 330+20 )
f = 440 ( 330/ 350 )
f = 440 ( 0.943 )
f = 414.9 Hz
Case 3. When the bus is moving away from the student
f = f₀ ( v / v+v₀ )
f = 440 ( 330/ 330-20 )
f = 440 ( 330/ 310 )
f = 440 ( 1.0645 )
f = 468.4 Hz
If you're moving, then you have kinetic energy.
If you're not at the bottom yet, then you still have
some potential energy left.