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UkoKoshka [18]
3 years ago
7

Answer this please. thanks in advance!! please tel me                                                                 a christma

s tree lights are set up in series
1. a set of lights has 50 bulbs  what will be the voltage across each bulb?
show your working out.
Physics
2 answers:
saw5 [17]3 years ago
6 0
If 50 identical light bulbs are connected in series across
a single power source, then the voltage across each bulb
is ( 1/50 ) of the voltage delivered by the power source.
4vir4ik [10]3 years ago
3 0
Presuming that this tree is connected into a mains power source in the UK. The total output of the UK mains source is 230V. So if we share this voltage equally between 50 bulbs:
230V \div 50 = 4.6V

I'm not 100 per cent sure this is correct though and different countries may have different mains power supplies. Hope it helps anyway.

EDIT: This also does not take into account resistance in the bulbs and wires but is all I can tell you from the information provided in the question.
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The electric motor of a model train accelerates the train from rest to 0.685 m/s in 21.5 ms. The total mass of the train is 875
Natali [406]

Answer:

P=9.58 W

Explanation:

According to Newton's second law, and assuming friction force as zero:

F_m=m.a\\F_m=0.875kg*a

The acceleration is given by:

a=\frac{\Delta v}{t}\\a=\frac{0.685m/s}{21.5*10^{-3}s}\\\\a=31.9m/s^2

So the force exerted  by the motor is:

F_m=0.875kg*31.9m/s^2\\F_m=27.9N

The work done by the motor is given by:

W_m=F_m*d\\\\d=\frac{1}{2}*a*t^2\\d=\frac{1}{2}*31.9m/s^2*(21.5*10^{-3}s)^2\\\\d=7.37*10^{-3}m

W_m=27.9N*7.37*10^{-3}m\\W_m=0.206J

And finally, the power is given by:

P=\frac{W_m}{t}\\P=\frac{0.206J}{21.5*10^{-3}s}\\\\P=9.58W

8 0
3 years ago
14. When incoming light rays strike a flat, plane mirror at an
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Answer:

close to the mirrors surface

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Add the following displacement vectors: <br> 12 m south and 15 m 55° E of N??
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4 0
3 years ago
A father is trying to teach his child to ice skate. As the child stands still, the father pushes him forward with an acceleratio
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Hi there!

We can use Newton's Second Law:

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6 0
3 years ago
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