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Furkat [3]
3 years ago
12

how does a jellyfish reproduce?explain the process and use the words polyp and medusa. hint my there are two stages of reproduct

ion
Chemistry
2 answers:
Readme [11.4K]3 years ago
6 0
The send a letter to the baby jellyfish factory. then they deliver babies to the parent. kinda like a stork would

Giddy up
Mazyrski [523]3 years ago
4 0
Jellyfish reproduction<span> involves several different stages. In the adult, or medusa, stage of a </span>jellyfish<span>, they can </span>reproduce<span>sexually by releasing sperm and eggs into the water, forming a planula. ... During this stage, which can last for several months or years, asexual </span>reproduction<span> occurs.</span>
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How many moles of potassium bromide (KBr) are in 97.569 grams? *
Tasya [4]

Answer:

nonofur bisnuse

Explanation:

fjiajrooooooooooooooooooooa;

3 0
3 years ago
The structure of an atom is defined by two numbers: the proton (atomic) number and the mass (nucleon) number. What is the electr
zzz [600]

Answer:

c

Explanation:

electronic configuration of  an atom with proton number 5 is 2, 3

since no. of proton = no. of electron

3 0
3 years ago
Help please I’m confused
Debora [2.8K]

Answer:1 answer number 1

Explanation:

5 0
3 years ago
4FeS2 + 11O2 &gt; 2Fe2O3 + 8SO2
BartSMP [9]

Answer:

80.13g of SO2

Explanation:

4FeS2 + 11O2 —> 2Fe2O3 + 8SO2

Molar Mass of FeS2 = 55.8 + (2x32) = 119.8g/mol

Mass of FeS2 from the balanced equation = 4 x 119.8 = 479.2

Molar Mass of SO2 = 32 + (16x2) = 32 + 32 = 64g/mol

Mass of SO2 from the balanced equation = 8 x 64 = 512g

From the equation,

479.2g of FeS2 produced 512g of SO2.

Therefore, 75g of FeS2 will produce = (75 x 512)/479.2 = 80.13g of SO2

3 0
4 years ago
Solutions of mercury (I) nitrate and potassium bromide are mixed
Afina-wow [57]
With that informatio you can:

1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.

I will do all four, for you:

1) Chemical equation:

mercury(I) nitrate  potassium bromide    mercury(I) bromide  potassium nitrate
<span>Hg2(NO3)2             +        KBr                   → Hg2Br2          +      KNO<span>3

2) Balanced chemical equation
</span></span>
<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3

3) Molar ratios or proportions:

1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3

4) Prediction of precipitation.

You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.


</span></span>
7 0
3 years ago
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