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2 years ago

What’s the relative size of gamma rays

Chemistry

2 answers:

Rzqust [24]2 years ago

5 0

Answer:

Less than 100 picometers (pm), or 4 x 10^9 inches.

Explanation:

Gamma-rays fall in the range of the EM spectrum above soft X-rays. Gamma-rays have frequencies greater than about 1,018 cycles per second, or hertz (Hz), and wavelengths of less than 100 picometers (pm), or 4 x 10^9 inches.

iren2701 [21]2 years ago

5 0

Answer: Gamma-rays have frequencies greater than about 1,018 cycles per second, or hertz (Hz), and wavelengths of less than 100 picometers (pm), or 4 x 10^9 inches.

Hope this helps! :)

Explanation:

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Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f

N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

Answer: The initial rate for the formation of C at 25°C is $2.25\times 10^{-2}Ms^{-1}$

Explanation:

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+2B\rightleftharpoons C$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b$

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first trial:

$5.4\times 10^{-3}=k(0.30)^a(0.050)^b$ ....(1)

Expression for rate law for second trial:

$1.1\times 10^{-2}=k(0.30)^a(0.100)^b$ ....(2)

Expression for rate law for third trial:

$2.2\times 10^{-2}=k(0.50)^a(0.050)^b$ ....(3)

Dividing 2 by 1, we get:

$\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1$

Dividing 3 by 1, we get:

$\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^1$ ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}$

Calculating the initial rate of formation of C by using equation 4, we get:

$k=1.2M^{-2}s^{-1}$

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

$\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}$

Hence, the initial rate for the formation of C at 25°C is $2.25\times 10^{-2}Ms^{-1}$

8 0

2 years ago

Select the correct answer from each drop-down menu. A student labels two 250 milliliter beakers with the letters A and B. She pu

Lelechka [254]

Answer:

The solution in beaker A is unsaturated

The solution in beaker B is saturated

Explanation:

A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. An unsaturated solution is a solution that contains less solute than it can normally hold at a particular temperature.

If more solute is added to a saturated solution, the added solute does not dissolve completely. However, if more solute is added to an unsaturated solution, the added solute dissolves.

4 0

2 years ago

Choose the answer below that gives the correct chemical symbol and classification (metal, metalloid, or nonmetal) for the elemen

Zielflug [23.3K]

Answer: B. The element called tin is a metal with the chemical symbol Sn.

Explanation:

A is incorrect because Ni is Nickel, not Niobium.

C is incorrect because Carbon is a nonmetal and its symbol is C, not Cr.

D is incorrect because Copper's symbol is Cu, not Ce.

E is incorrect because As is the symbol for Arsenic, not Astatine.

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2 years ago