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2 years ago

What’s the relative size of gamma rays

Chemistry

2 answers:

Rzqust [24]2 years ago

5 0

Answer:

Less than 100 picometers (pm), or 4 x 10^9 inches.

Explanation:

Gamma-rays fall in the range of the EM spectrum above soft X-rays. Gamma-rays have frequencies greater than about 1,018 cycles per second, or hertz (Hz), and wavelengths of less than 100 picometers (pm), or 4 x 10^9 inches.

iren2701 [21]2 years ago

5 0

Answer: Gamma-rays have frequencies greater than about 1,018 cycles per second, or hertz (Hz), and wavelengths of less than 100 picometers (pm), or 4 x 10^9 inches.

Hope this helps! :)

Explanation:

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How many grams of the excess reactant are left over according to the reaction below given that you start with 10.0 g of Al and 1

valentinak56 [21]

4 Al + 3 O2 → 2 Al2O3

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2

0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.

((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over

7 0

3 years ago

Read 2 more answers

What is the pH of a solution has a hydrogen ion concentration of 6.3 x 10–10 M? Show work

NISA [10]

Answer:

pOH = 4.8

pH = 9.2

Explanation:

Given data:

Hydrogen ion concentration = 6.3×10⁻¹⁰M

pH of solution = ?

pOH of solution = ?

Solution:

Formula:

pH = -log [H⁺]

[H⁺] = Hydrogen ion concentration

We will put the values in formula to calculate the pH.

pH = -log [6.3×10⁻¹⁰]

pH = 9.2

To calculate the pOH:

pH + pOH = 14

We will rearrange this equation.

pOH = 14 - pH

now we will put the values of pH.

pOH = 14 - 9.2

pOH = 4.8

7 0

3 years ago

Greg has 36 DVDs in his collection.

sp2606 [1]

Answer:

Explanation:

4 0

3 years ago

The equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of ox

Vaselesa [24]

0.0292 moles of sucrose are available. First, lookup the atomic weights of all involved elements Atomic weight Carbon = 12.0107 Atomic weight Hydrogen = 1.00794 Atomic weight Oxygen = 15.999 Now calculate the molar mass of sucrose 12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol Divide the mass of sucrose by its molar mass 10.0 g / 342.29208 g/mol = 0.029214816 mol Finally, round the result to 3 significant figures, giving 0.0292 moles

7 0

2 years ago

A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t

gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

$C_{1}$ $V_{1}$ = $C_{2}$ $V_{2}$ , where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.