Question

Which sample contains more atoms: 3.89 g of nickel or 6.61 g of silver? defend your answer

Answer 1

Nickel contains more atoms.

Explanation:

Number of atoms is determined by the Avogadro number.

1 mole of substance contains 6.022 X 10²³ atoms.

Given:

Mass of Nickel, Ni = 3.89g

Molecular weight of Ni = 58.6934g

Number of moles of Ni = 3.89/58.6934g

Number of atoms of Ni = $\frac{3.89 X 6.022 X 10^2^3}{58.6934}$

Number of atoms of Ni = 0.39 X 10²³

Mass of silver, Ag = 6.61g

Molecular weight of Ag = 107.8682g

Number of moles of Ag = 6.61/107.8682

Number of atoms of Ag = $\frac{6.61 X 6.022 X 10^2^3}{107.8682}$

Number of atoms of Ag = 0.36 X 10²³

Therefore, Nickel contains for atoms.