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3 years ago

HELPPP simply the expression!!!!

Chemistry

1 answer:

coldgirl [10]3 years ago

4 0

Answer:

$\frac{3}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{3 \sqrt{3} }{3} = \sqrt{3}$

when there is a radical in the denominator, we should rationalize (mutiply the denominator and numerator by the radical) to get rid of the radical in the denominator.

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Describe how sediments are produced by weathering and erosion

TEA [102]

Weathering is the physical or chemical process where rocks are broken down to form sediments.
• Physical weathering does not change the rock’s composition.
• Chemical weathering does change the rock’s composition
• Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location

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4 years ago

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Which atom would be expected to have a half-filled 6s subshell

eduard

Answer: I think the answer is Cesium (Cs)

Explanation:

A half-filled 6s subshell would be 6s^1

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3 years ago

Is making ice cream a physical or chemical change

harina [27]

Answer:

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Explanation:

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3 years ago

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A 1.20-L container contains 1.10 g of an unknown gas at STP. What is the molecular weight of the unknown gas?

SOVA2 [1]

Answer:

M = 20.5 g/mol

Explanation:

Given data:

Volume of gas = 1.20 L

Mass of gas = 1.10 g

Temperature and pressure = standard

Solution:

First of all we will calculate the density.

Formula:

d = mass/ volume

d = 1.10 g/ 1.20 L

d = 0.92 g/L

Now we will calculate the molar mass.

d = PM/RT

0.92 g/L = 1 atm × M / 0.0821 atm.L/mol.K ×273.15 K

M = 0.92 g/L × 0.0821 atm.L/mol.K ×273.15 K / 1 atm

M = 20.5 g/mol

8 0

3 years ago

What is the partial pressure of radon if the total pressure is 780 torr and the

Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure = 780torr

Partial pressure of water vapor = 1.0atm

Unknown:

Partial pressure of radon = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

P $_{t}$ = P $_{1}$ + P $_{2}$ + P $_{n}$

Since the total pressure is 780torr, convert this to atm;

760torr = 1 atm

780torr = $\frac{780}{760}$ atm = 1.03atm

For this problem;

Total pressure = Partial pressure of radon + Partial pressure of water vapor

1.03 = Partial pressure of radon + 1.0

Partial pressure of radon = 1.03 - 1.00 = 0.03atm

6 0

3 years ago