Explanation:
It is known that relation between ,
, and pH is as follows.
Also, it is known that for hydrogen is equal to zero.
Hence, substituting the given values into the above equation as follows.
0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}] [/tex]
= 4.03
= antilog 4.03
= 3.5
As, pH = .
Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.