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OLEGan [10]
3 years ago
9

The ball and socket joint in the hip is similar to the ball and socket joint of the shoulder but is designed more for __________

than ___________.
Physics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

a. power

b. precision

Explanation:

The hip is a spherical joint that allows the upper leg to move from front to back and from side to side. The largest joint that supports weight in the body, the hip joint is surrounded by strong ligaments and muscles.

It differs mainly with the circular articulation of the shoulder since it allows it to perform movement of greater power and with greater precision

kondaur [170]3 years ago
5 0

Answer:

The ball and socket joint in the hip is similar to the ball and socket joint in the shoulder, but is designed <em>more</em> for bio-mechanical strength, stability and ability to carry weight than a wide range of movement.

Explanation:

The kind of weights that the hips carry vary in nature.

Some weights are better described as stationary and others as ,constantly changing.  

Besides carrying it's own weight (that is the upper torso), the hip is also active and instrumental in the ability of mankind to lift and carry additional weights.

The study of how the hip manages these weights effortlessly is important in the design of prosthetic appendages and replacement hips for accident victims and geriatric patients who have one hip issue or the other.

Cheers!

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The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
WINSTONCH [101]

Answer:

8000J

Explanation:

The kinetic energy of the car lost during breaking are converted to thermal energy and are gained by the brakes.

Kinetic energy loss by car = thermal energy gained by brakes.

∆K.E = ∆T.E ....1

The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

Initial K.E = K.E1 = 10000J

Final K.E = K.E2 = 2000J

∆K.E= 10000J - 2000J = 8000J

From equation 1,

∆K.E = ∆T.E

∆T.E = 8,000J

thermal energy gain by brakes = 8,000J

8 0
3 years ago
The frequency of the George Washington Bridge is 2.05 Hz. What is its period?
Zina [86]

Answer: 0.5 seconds

Explanation:

Given that:

Frequency of the George Washington Bridge F = 2.05 Hz

Period T = ?

Recall that frequency is the number of cycles a wave can complete in one second. Hence, frequency is the inverse of period.

i.e F = 1/T

2.05Hz = 1/T

T = 1/2.05Hz

T = 0.488 seconds (Rounded to the nearest tenth as 0.5seconds)

Thus, the period of the George Washington Bridge is 0.5 seconds

6 0
3 years ago
when mary took a cold thick-walled glass out of the refrigerator and placed it in boiling water, the glass cracked. Explain why
goldfiish [28.3K]
The outer surface of the glass expands faster than the inside surface since glass is a fairly good thermal insulator. The outer surface tries to expand without the inner surface doing so at the same time. This is the secret of Pyrex glass. It is more conductive to heat and the inner and outer surface expand (and contract) at the same time.

4 0
3 years ago
Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direc
Lerok [7]

Answer:

424.26 m/s

Explanation:

Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q

The relative speed will be calculated by using pythagorean theorem

Relative speed = sqrt(300^2 + 300^2)

Relative speed = sqrt( 180000 )

Relative speed = 424.26 m/s

Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s

7 0
3 years ago
Ship A is located 4.1 km north and 2.3 km east of ship B. Ship A has a velocity of 22 km/h toward the south and Ship B has a vel
castortr0y [4]

Answer:

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

Explanation:

Given data:

A position is 4km north and 2.5 km east to B

Ship A velocity = 22 km/hr

ship B velocity = 40 km/hr

A velocity wrt to velocity of B

\vec{V_{AB}} =\vec{V_A} - \vec{V_B}

\vec{V_A} = 22 km/hr

\vec{V_B} = 40 cos38\hat{i} + 40sin 38 \hat{j}

                 = 31.52\hat{i} + 24.62 \hat{j}

putting respective value to get velocity of  A with respect to B

\vec{V_{AB}} = -22 \hat {j} - (31.52\hat{i} + 24.62 \hat{j})

\vec{V_{AB}} = -31.52\hat{i} - 46.62\hat{j}

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

6 0
3 years ago
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