Answer:
= 0.417 m/s
Explanation:
Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s
= 44.27 N*s
A) man throws the rock forward
mass of rock m1 = 0.310 kg
V1 = 15.5 m/s, in the same direction of the sled with the man
sled and man:
m2 = 95 kg - 0.310 kg = 94.69 kg
v2 = ?
Conservation of momentum:
momentum before throw = momentum after throw
44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2
⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg
= 0.417 m/s
Answer:
her acceleration is 1 m/sec
Explanation:
The following information is given in the question
The initial velocity is 5 m/s
After 10 seconds, she would be moved at 15 m/s
We need to find the acceleration
As we know that
Acceleration = Change in speed ÷ time
Acceleration = (15 - 5) ÷ (10)
= 1 m/sec
Hence, her acceleration is 1 m/sec
The same would be considered
Well, you haven't given us much of a choice of graphs to pick from, have you.
If a sample of an ideal gas is held at constant temperature, then
its pressure and volume are inversely proportional ... the harder
you squeeze it, the smaller the volume gets, and less squeeze
produces more volume.
Actually, the product of (pressure) x (volume) is always the
same number.
The graph of that relationship is all in the first quadrant.
It starts out very high right next to the y-axis, then drops down
toward the x-axis while curving to the right and becoming horizontal,
and ends up trying to get closer and closer to the x-axis but never
actually becoming zero.
Answer:d
Explanation:
From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.
Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.
and to counter it there is q charge on the surface. So total charge outside the surface is Q+q
2 m/s/s means the velocity increases by 2 m/s every second.
