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Anastasy [175]
3 years ago
12

In a sound wave, the maximum displacement of the air molecule from it's undisturbed position is called _______________.

Physics
1 answer:
professor190 [17]3 years ago
6 0
It's called amplitude...
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An is holding an ice cube. What causes the ice to melt?
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Answer: A... Thermal energy from the ice is transferred to the air.

Explanation: because I just know.

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2 years ago
A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th
SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

   Volume = 470 cm³

   Density = 3.55 g/cm³

   Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

   Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

   Volume = 470 cm³

   Density of liquid = 1 g/cm³

   \texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N

c) Mass of the water displaced = Volume of body x Density of liquid

   Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

   Weight of rock under water = 16.37 - 4.61  =11.76 N

3 0
3 years ago
Since acids are so corrosive they are not found anywhere in the human body true/false
pantera1 [17]

the answer is in fact True

5 0
3 years ago
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Science Help Please?? It is believed that solar nebular material came from which of the following:
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B would be the answer to this
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2 years ago
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A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building hori
tamaranim1 [39]
In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,

   d = V₀t + 0.5gt²

Substituting the known values,

  225 = (0 m/s)(t) + (0.5)(9.8)(t²)

Simplifying,
 
   t = 6.776 s

To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.


   range = (12.5 m/s)(6.776 s)

   range = 84.7 m

<em>Answer: 84.7 m</em>

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2 years ago
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