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Anastasy [175]
3 years ago
12

In a sound wave, the maximum displacement of the air molecule from it's undisturbed position is called _______________.

Physics
1 answer:
professor190 [17]3 years ago
6 0
It's called amplitude...
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What is the answer!!!!!!!!!!!!!
alex41 [277]
I think it might be B. 
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3 years ago
A rock group is playing in a bar. Sound emerging from the door spreads uniformly in all directions. The intensity level of the m
LekaFEV [45]

Answer:

1779299.7m

Explanation:

From formulas in acoustic sound, we know that sound intensity is inversely proportional to the square of the distance away.

Thus;

I2/I1 = r2²/r 1²

So,

∆L = 10 log (I2/I1)

Where ∆L is the intensity of music and r1 and r2 are distances away.

∆L=10log 10(r1²/r2²)

∆L=10log 10(r1/r2)²

∆L= - 20log 10(r1/r2)

r2 = r1•10^(-∆L/20)

​From the question,

∆L = 116 Db

r1 = 2.82m

Thus,

r2 = 2.82 x 10^(116/20)

r2 = 2.82 x 630957.34 = 1779299.7m

5 0
3 years ago
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What discovery lead J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts? Thomson
Margaret [11]
Thomson used a beam of negatively charged particles.
8 0
3 years ago
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If the average velocity of a duck is zero in a given time interval, what can you say about the displacement of the duck for that
Gemiola [76]

Answer:

Also 0

Explanation:

Since average speed of an object is that object's displacement over a unit of time, when an average speed is 0, its displacement over a unit of time must also be 0. When an average speed is not 0, then its displacement over a unit of time is also not 0 for that interval.

6 0
3 years ago
An unbanked circular highway curve on level ground makes aturn
tino4ka555 [31]

Answer:

Explanation:

Given

Velocity of traffic v=60\ mi/hr\approx 26.82\ m/s

Maximum value of Centripetal force is one-tenth of weight

such that (F_c)_{max}=\frac{mg}{10}

to make a safe turn centripetal force with radius of curvature r is given by

F_c=\frac{mv^2}{r}

(F_c)_{max}=\frac{mg}{10}=F_c=\frac{mv^2}{r}

\frac{mg}{10}=\frac{mv^2}{r}

r=\frac{10v^2}{g}

r=\frac{10\times 26.82^2}{9.8}

r=733.99\approx 734\ m

     

4 0
4 years ago
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