You could use the formula
W=Fd
F(force)=20N
D(distance/displacement) =15m
W=(20N)(15m)
W= 300 J
Answer:
the destiny of water is 997 kg/m^3, hope this helps :)
Answer:
When the heat is heated it will be melted of ice, why it still remain at a constant temperature of 0◦ C.
Explanation:
Solution
The heat given by the heater will be used in melting of the ice, therefore the temperature will remain the same at the degree of 0◦ C.
After the ice is fully melted, the temperature of water will begin to increase with time.
Note: kindly find an attached document of the solutions with diagrams as part of this explanation
Answer: A
Explanation:
From the question, the given parameters are given.
Mass M = 30kg
Radius r = 2 m
Coefficient of static friction μ = 0.8
Coefficient of kinetic friction μ = 0.6
Kinetic friction Fk = μ × mg
Fk = 0.6 × 30 × 9.8
Fk = 176.4 N
The force acting on the merry go round is a centripetal force F.
F = MV^2/r
This force must be greater than or equal to the kinetic friction Fk. That is,
F = Fk
F = 176.4
Substitute F , M and r into the centripetal force formula above
176.4 = (30×V^2)/2
Cross multiply
352.8 = 30V^2
V^2 = 352.8/30
V = sqrt (11.76) m/s
V = 5.24 m/s
Therefore, the maximum speed of the merry go round before the child begins to slip is sqrt (12) m/s approximately
I beleve it is 15 if not sorry
