Anybody know these ?
1 answer:
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Answer:
Explanation:
a) using the energy conservation equation
mgh = 0.5mv^2 + 0.5Iω^2
I(moment of inertia) (basket ball) = (2/3)mr^2
mgh = 0.5mv^2 + 0.5( 2/3mr^2) ( v^2/r^2)
gh = 1/2v^2 + 1/3v^2
gh = v^2( 5/6)
v =
putting the values we get
solving for h( height)
h = 3.704 m apprx
b) velocity of solid cylinder
mgh = 0.5mv^2 + 0.5( mr^2/2)( v^2/r^2) where ( I ofcylinder = mr^2/2)
g*h = 1/2v^2 + 1/4v^2
g*h = 3/4v^2
putting the value of h and g we get
v= = 6.957 m/s apprx
Answer:
<em>The displacement of the object is -8 m</em>
Explanation:
<u>Displacement</u>
The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.
If the area is below the y-axis, then the displacement is negative. Otherwise is positive.
It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.
From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.
The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:
The displacement of the object is -8 m