Answer:
The final temperature of the mixture = 64.834 °C.
Explanation:
Heat lost by the silver ring = heat gained by the water + heat transferred to the surrounding.
c₁m₁(t₁-t₃) = c₂m₂(t₃-t₂) + Q..............Equation 1
Where c₁ = specific heat capacity of the silver copper, m₁ = mass of the silver copper, t₁ = initial temperature of the silver copper, t₃ = final temperature of the mixture. c₂ = specific heat capacity of water, t₂ = initial temperature of water, m₂ = mass of water, Q = energy transferred to the surrounding.
making t₃ the subject of the equation,
t₃ = [c₁m₁t₁+c₂m₂t₂-Q]/(c₁m₁+c₂m₂)........................ Equation 2
Given: c₁ = 234 J/kg.°C, m₁ = 26.4 g, t₁ = 66.2 °C, c₂ = 4200 J/K.°C, m₂ = 4.92×10⁻² kg, t₂ = 24.0 °C, Q = 0.136 J.
Substituting into equation 2
t₃ = [(234×26.4×66.2)+(4200×0.0492×24)-0.136]/[(234×26.4)+(4200×0.0492)]
t₃ = (408957.12+4959.36-0.136)/(6177.6+206.64)
t₃ = (413916.48-0.136)/6384.24
t₃ = 413916.34/6384.24
Thus the final temperature of the mixture = 64.834 °C.
