Answer:
V = 25.3 , θf = 36.7° below the horizontal
Explanation:
Given Vo = 22m/s , θ = 23°
Vx = VoCosθ
Vy = VoSinθ – gt
t = total time of flight
Answer:
A. 490
Explanation:
soln
mass = m = 5kg
Height = h = 10m
Acceleration due to gravity = g = 9.8ms²
K.E = 1/2 × mass × (velocity)²
Recall from equations of motion
v² = u² + 2gh
Therefore,
K.E = 1/2 × mass × ( u² + 2gh)
K.E = 1/2 × 5 × ( 0² + 2×10×9.8)
K.E = 1/2 × 5 × 196
K.E = 1/2 × 980
K.E = 490 Joules
In what language are you speaking?
Answer:
K.E = 0.0075 J
Explanation:
Given data:
Mass of the ball = 1.5 kg
radius, r = 50 cm = 0.5 m
Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec
Now,
the kinetic energy is given as:
K.E = 
where,
I is the moment of inertia = mr²
on substituting the values, we get

or
K.E = 0.0075 J