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olga nikolaevna [1]
3 years ago
5

Which quantity and unit are INCORRECTLY paired?

Physics
1 answer:
liq [111]3 years ago
5 0
Force, the unit is Newton, newton is the force to accelerate a mass. so it should be kg m/s^2

joule (J) is equal to Nm not Ns

the unit of work is J and it is correct.
the unit of power is J/s which is equal to W
the unit of of energy is the same with work, which is J which equivalent to kgm2/s2
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A straight section of silver wire has a cross sectional area A=2.0 mm2. A total of 9.4×1018 electrons pass through the wire in 3
Sergio [31]

Answer:

8.08 x 10^-5 m

Explanation:

A = 2 mm^2 = 2 x 10^-6 m^2

Total number of electrons, N = 9.4 x 10^18

time, t = 3 s

n = 5.8 x 10^28 electrons/ m^3

Current, i = Q / t = N x e / t = (9.4 x 10^18 x 1.6 x 10^-19) / 3 = 0.5 A

Let vd be the drift velocity.

i = n e A vd

0.5 = 5.8 x 10^28 x 1.6 x 10^-19 x 2 x 10^-6 x vd

vd = 2.7 x 10^-5 m/s

Distance traveled by the electrons = velocity x time

                                                          = vd x t = 2.7 x 10^-5 x 3 = 8.08 x 10^-5 m  

3 0
3 years ago
The distance between the first and fifth minima of a single-slit diffraction pattern is 0.500 mm with the screen 37.0 cm away fr
WARRIOR [948]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y_n= \frac{n \lambda D}{a} (1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
D=37.0 cm=0.37 m
\lambda=530 nm=5.3 \cdot 10^{-7} m
while the distance between the first and the fifth minima is
y_5-y_1 = 0.500 mm=0.5 \cdot 10^{-3} m (2)

If we use the formula to rewrite y_5, y_1, eq.(2) becomes
\frac{5 \lambda D}{a} - \frac{1 \lambda D}{a} =\frac{4 \lambda D}{a}= 0.5 \cdot 10^{-3} m
Which we can solve to find a, the width of the slit:
a= \frac{4 \lambda D}{0.5 \cdot 10^{-3} m}= \frac{4 (5.3 \cdot 10^{-7} m)(0.37 m)}{0.5 \cdot 10^{-3} m}=  1.57 \cdot 10^{-3} m=1.57 mm

7 0
3 years ago
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B) colloid because i took the test and that the answer

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