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HACTEHA [7]
3 years ago
12

The distance between the fixed point of a Celsius thermometer is20cm. what is the temperature when the mercury level is 4.5cm ab

ove the lower mark?​
Physics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

22.5°C

Explanation:

Given height of Celsius thermometer is 20 cm.

As we know the limit of a Celsius thermometer is 100°C

It is given that total height of thermometer is 20 cm.

So, this limit that is 100°C should be equal to 20 cm.

20\ cm\ =\ 100°C

1\ cm\ =\ \frac{100}{20}°C

1\ cm\ =\ 5°C

Now, we want to find the temperature when the level of mercury was 4.5 cm.

4.5\ cm\ =\ 5\times 4.5°C

4.5\ cm\ =\ 22.5°C

Hence, we have 22.5°C temperature in Celsius thermometer when height of mercury is 4.5 cm above the lower mark.

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Why are fossils more commonly found in sedimentary rocks and not igneous rocks?
stiv31 [10]

The reason you only see fossils in sedimentary rock is that these set of rocks are formed in much lower pressure and temperature, compared to the other types of rocks like igneous rocks.

7 0
3 years ago
At a certain point in space there is a potential of 400 v. what is the potential energy of a 2-μc charge at that point in space?
attashe74 [19]

The potential energy of a 2-μc charge at that point in space is 8*10^{-4} joules.

Given,

V=400v, q=2-μc=2*10^{-6},

U(potential energy)=V*q=400*2*10^{-6}= 8*10^{-4} joules.

<h3>Potential energy</h3>

The energy that an item retains due to its position in relation to other objects, internal tensions, electric charge, or other reasons is known as potential energy in physics. The gravitational potential energy of an object is based on its mass and the distance from the centre of mass of another object. Other common types of potential energy include the elastic potential energy of an extended spring and the electric potential energy of an electric charge in an electric field. The joule, denoted by the sign J, is the SI's definition of an energy unit.

The vectors that are described as gradients of a particular scalar function known as potential can be used to represent these forces, also known as conservative forces, at any location in space.

At a certain point in space there is a potential of 400 v. what is the potential energy of a 2-μc charge at that point in space? group of answer choices'

Learn more about potential energy here:

brainly.com/question/15764612

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8 0
2 years ago
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its e
kirill115 [55]

Answer:

378 KWh

Explanation:

We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:

10³ W = 1 KW

Therefore,

1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W

1.2×10³ W = 1.2 KW

Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:

60 mins = 1 h

Therefore,

6.3×10² mins = 6.3×10² mins × 1 h / 60 mins

6.3×10² mins = 10.5 h

Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:

Power (P) = 1.2 KW

Time (t) for 1 month (30 days) = 10.5 h × 30

= 315 h

Energy (E) =?

E = Pt

E = 1.2 × 315

E = 378 KWh

Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.

8 0
3 years ago
What is the primary difference between an ideal emf device and a real emf device?.
EleoNora [17]

Answer:

A real emf device has an internal resistance, but an ideal emf device does not.

3 0
2 years ago
Read 2 more answers
A satellite in the shape of a solid sphere of mass 1,900 kg and radius 4.6 m is spinning about an axis through its center of mas
algol [13]

Answer:

6.3 rev/s

Explanation:

The new rotation rate of the satellite can be found by conservation of the angular momentum (L):

L_{i} = L_{f}

I_{i}*\omega_{i} = I_{f}*\omega_{f}

The initial moment of inertia of the satellite (a solid sphere) is given by:

I_{i} = \frac{2}{5}m_{s}r^{2}

Where m_{s}: is the satellite mass and r: is the satellite's radium

I_{i} = \frac{2}{5}m_{s}r^{2} = \frac{2}{5}1900 kg*(4.6 m)^{2} = 1.61 \cdot 10^{4} kg*m^{2}

Now, the final moment of inertia is given by the satellite and the antennas (rod):

I_{f} = I_{i} + 2*I_{a} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}m_{a}l^{2}

Where m_{a}: is the antenna's mass and l: is the lenght of the antenna

I_{f} = 1.61 \cdot 10^{4} kg*m^{2} + 2*\frac{1}{3}150.0 kg*(6.6 m)^{2} = 2.05 \cdot 10^{4} kg*m^{2}

So, the new rotation rate of the satellite is:

I_{i}*\omega_{i} = I_{f}*\omega_{f}

\omega_{f} = \frac{I_{i}*\omega_{i}}{I_{f}} = \frac{1.61 \cdot 10^{4} kg*m^{2}*8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kg*m^{2}} = 6.3 rev/s  

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

I hope it helps you!  

5 0
4 years ago
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