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3 years ago

A circuit is built based on the circuit diagram shown. What is the current in the 50 Ω resistor

Physics

1 answer:

In-s [12.5K]3 years ago

5 0

Answer:

1.2 A

Explanation:

From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:

Voltage (V) = Current (I) × Resistance (R)

V = IR

I = V/R

I = 60 V/ 50 Ω

I = 1.2 A

The current in the 50 Ω resistor is 1.2 A

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A new mechanic foolishly connects an ammeter with 0.1 Ω resistance directly across a 12-V car battery with internal resistance o

NemiM [27]

Answer:

The power dissipated by the meter is 1188W

Explanation:

Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:

$P=I^2R_m$

We first need to fin the current going through the circuit:

$I=\frac{V}{R}\\where:\\V=voltage\\R=resistance$

$R=R_s+R_m$

because they are connected in series. So:

$I=\frac{12V}{(0.01+0.1)}=109A$

$P=(109)^2*0.1=1188W$

8 0

3 years ago

Consider the reaction.

BaLLatris [955]

Answer:

Explanation:

Consider the reaction.A(g)↽−−⇀Z(g)A

(

)

↽

−

⇀

(

)

The equilibrium constant,

, expresses the relationship between the concentrations of the species at equilibrium.

(g)

The energy of A-A bond in A is 98 kJ/mol. The energy of Z-Z bond in Z is 165 kJ/mol. Which statement about the reaction is correct?

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

5) The energy of A-A bond in A is greater than the energy of Z-Z bond in Z.

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

It is correct that the activation energy for Reaction ↽−+X(g)AX(g) is smaller than that for Reaction ⇀+AX(g)↽−, because AX is less stable than A or Z, so it takes less energy to break the weaker bond in AX.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

Option (2) is incorrect because, though the formation of AX requires energy, which is not needed for the formation of A or Z; however, the total energy required to break both A-A and Z-Z bonds (above) is more than the amount released when A and Z combine to form AX.

Option (3) is incorrect because the amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

8 0

3 years ago

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the

Marina86 [1]

Answer:

a) The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) The Ferris wheel takes 14.646 seconds to make a revolution.

Explanation:

a) An object that rotates at constant angular velocity reports a centripetal acceleration and no tangential acceleration. When passenger passes through the lowest point in her circular motion, centripetal acceleration goes up to the center.

In addition, centripetal acceleration is determined by the following expression:

$a_{R} = \frac{v^{2}}{R}$ (Eq. 1)

Where:

$a_{R}$ - Centripetal acceleration, measured in meters per square second.

$v$ - Linear speed, measured in meters per second.

$R$ - Radius of the Ferris wheel, measured in meters.

If we know that $v = 6\,\frac{m}{s}$ and $R = 14\,m$ , the magnitude of radial acceleration is:

$a_{R} = \frac{\left(6\,\frac{m}{s} \right)^{2}}{14\,m}$

$a_{R} = 2.571\,\frac{m}{s^{2}}$

The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) In the highest point the magnitude of radial acceleration is the same but direction is the opposed to that at lowest point. That is, centripetal acceleration goes down to the center.

Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) At first we need to calculate the angular velocity of the Ferris wheel ( $\omega$ ), measured in radians per second, by using the following expression: