The solution would be like this for this specific problem:
Given:
Oil spill radius constant rate increase = 1 m/s
r = 34m
Let the area of the spill
be A and then let its radius be r. <span>
Then A = π r². </span>
Differentiating with
respect to t: <span>
dA / dt = 2π r dr / dt. </span>
Substituting r = 34 and dr
/ dt = 1:
dA/dt = 2 π * r * dr / dt
dA/dt = 2π * 34 * 1 = 68π
= 214 m²/s, to 3 significant figures.
<span>So, given that the radius
is 34m, then the area of the spill is increasing at 214 m²/s.</span>
C transformability i think
Answer:
b and e
Explanation:
r x F is the formula for torque.
The "turning effect" or torque happens when concentric forces rotate an object along said center.
a) False because T = Fr = Ia (a = angular acceleration)
b) True
c) False. L = Iw (w = angular velocity), which does not equal Ia
d) False. It is torque, not the product of torque and something else
e) True.
Answer:
5.5 N at 50.8° north of west.
Explanation:
To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.
The three forces are:
(east)
(west)
(at 60° north of west)
Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:
Threfore, the components of the resultant force are:
Therefore, the magnitude of the resultant force is
And the direction is:
And since the x-component is negative, it means that this angle is measured as north of west.
Factor out 8 and then facotr and u get
8/9(9x+1)(9x-1
