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2 years ago

Calculate the current if a charge of 5.60C passes through a point in a conductor in 15.4s

Physics

1 answer:

Ulleksa [173]2 years ago

7 0

Electric current is defined as charge per time in units of Coulombs/second
So we have
I=5.6C/15.4s = 0.3636A

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A baby carriage is sitting at the top of a hill that is 35 m high. The

Lemur [1.5K]

P=M(mass)G(Gravity)H(Height)

Gravity=9.8

M=1.5 G=9.8 H=35

so multiply all

=514.5 potential energy

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2 years ago

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We have an Atwood device, two blocks connect by a string strung over a pulley, but the twist this time is that both blocks are o

Zanzabum

The Acceleration of the system is 6.41 m/s².

Given,

α= 15°, m₁ = 7kg

β= 65°, m₂ = 11 kg

Let, a be the acceleration and T is the tensions at the end it's the cord.

Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,

Resultant force, m₂a=m₂g sin β -T

11a=((11) ×g sin 65°) -T ...(i)

Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.

Resultant force m₁a = m₁g sin α+T

7a =7g sin 15°+T ...(ii)

Solving both the equations by adding them,

18a=11gsin 65°+7g sin 15°-T+T

18a=11gsin 65°+7g sin 15°=115.45

a=115.45/18=6.41 m/s²

Hence, the Acceleration of the system is 6.41 m/s².

Learn more about the acceleration here:

brainly.com/question/22048837

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2 years ago

How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00

klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is $9 \times 10^{-4} m^{2}$ . As the capacitance of capacitor is given as follows.

C = $\frac{\epsilon_{o}A}{d}$

It is known that the dielectric strength of air is as follows.

E = $3 \times 10^{6} V/m$

Expression for maximum potential difference is that the capacitor can with stand is as follows.

dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

Q = CV

= $\frac{\epsilon_{o} A}{d} \times E \times d$

= $\epsilon_{o}AE$

= $8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}$

= $1.062 \times 10^{-8} C$

or, = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

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3 years ago

On a roller coaster, describe the kinetic and potential energy of the car at the top of the first hill, the bottom of the first

vaieri [72.5K]

The total amount of energy stays the same, but throughout the ride, the kinetic energy and the potential energy change, still adding up to the same number. At the top of the ride it has potential energy, and as it goes down the potential energy decreases and the kinetic energy increases. When it’s at the bottom of the first drop it has maxed out its kinetic energy, and minimized its potential energy. Friction slows down the car, and pushes on the cart with a force that is equal and opposite to the force being exerted in the track. The reason the track keeps going is because though it exerts and equal and opposite force the momentum of the objects is different, allowing the car to continue moving, however friction will slow it down until eventually it comes to a stop.

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3 years ago

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The Millennium Falcon was constructed 43.6 m long. a) How fast is it traveling past Luke when he measures its length to be 30.1

Zinaida [17]

Answer:

a)0.5564c

b)43.6 m

Explanation:

Given proper length of falcrum L₀= 43.6 m

improper length L=30.1 m (when viewed from moving frame)

we know that $L=L_{0}\sqrt{1-\frac{v^2}{c^2}}$

$30.1=43.6\sqrt{1-\frac{v^2}{c^2}$

⇒ $\{1-\frac{v^2}{c^2}}$ = $\frac{30.1}{43.6}$

${1-\frac{v^2}{c^2}}=0.6904$

$\frac{v^2}{c^2}=0.3096$

$v^{2}=3096c^{2}$

v=0.5564c

this is the required speed of falcon when it passes luke

b). Since Han solo is on the Falcon its reference frame will be falcon itself hence there wont be any change in the length of Falcon that its length will be

43.6 m

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2 years ago