What is 726x5 estimated

The graph of f(x) = StartRoot x EndRoot is reflected across the x-axis and then across the y-axis to create the graph of functio

allsm [11]

Answer:

The true statements:

The only value that is in the domains of both functions is 0.

The range of g(x) is all values less than or equal to 0.

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Step-by-step explanation:

See the attached figure:

As shown: f(x) = √x with blue color

When f(x) is reflected across the x-axis the result will be (-√x) with red color.

Then the is reflected result across the y-axis to create the graph of function g(x) = -√(-x) with green color.

Domain of f(x) = [0,∞) & Range of f(x) = [0,∞)

Domain of g(x) = (-∞,0] & Range of g(x) = (-∞,0]

So, according to previous, we will check the statements:

1) The functions have the same range. (Wrong)

2) The functions have the same domains. (Wrong)

3) The only value that is in the domains of both functions is 0. (True)

4) There are no values that are in the ranges of both functions. (Wrong)

5) The domain of g(x) is all values greater than or equal to 0. (Wrong)

6) The range of g(x) is all values less than or equal to 0. (True)

8 0

3 years ago

Read 2 more answers

(05.05 LC)

Phantasy [73]

Answer:

A. $6

Step-by-step explanation:

We are given the table representing the number of days and the total charges in dollars.

So, the rate of change of the amount is given by, $\frac{16-6}{1-0}=\frac{26-16}{2-1}=10$

The linear equation representing the situation is,

Total charges = Fee per days + Fixed amount.

i.e. Total charges, y = Rate multiplied by x + Fixed amount (c)

So, substituting the rate and the point (0,6), we get,

6 = 10 × 0 + c

i.e. c = 10

Thus, the equation is,

Total charges, y = Rate multiplied by x + Fixed amount (c)

i.e. y = 10x + 6

Hence, the fixed amount charged is $6.

So, option A is correct.

4 0

3 years ago

The Sun is roughly 10^2 times as wide as the Earth. The Star KW Sagittarii is roughly 10^5 times as wide as the Earth. About how

Studentka2010 [4]

Answer:

1000 times

Step-by-step explanation:

Given:

The Sun is roughly 10^2 times as wide as the Earth.

The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.

Question asked:

About how many times as wide as the Sun is KW Sagittarii?

Solution:

Let the width of the earth = $x$

As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = $x\times10^{2}$

And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = $x\times10^{5}$

Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:

Width of the Star KW Sagittarii = $x\times10^{5}$

Width of the Sun = $x\times10^{2}$

$\frac{x\times10^{5} }{x\times10^{2} }$

x canceled by x

$\frac{10^{5} }{10^{2} } =10^{5-2} =10^{3} =10\times\ 10\times10=1000$

Therefore, Star KW Sagittarii is 1000 times wider than Sun.

First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.

4 0

3 years ago

Micheal buys two bags or chips and three boxes of pretzels for $5.13 . He then buys another bag of chips and 2 boxes of pretzels

trapecia [35]

Answer:

So a bag of chip costs $2.39

Step-by-step explanation:

Let x = cost of a bag of chip

Let y = cost of a box of pretzel

Micheal buys two bags of chips and three boxes of pretzels for $5.13

This means

2x + 3y = 5.13 - - - - - - - - - -1

He then buys another bag of chips and 2 boxes of pretzels for $3.09

This means

x + 2y = 3.09 - - - - - - - - - - - -2

Solving equation 1 and equation 2 simultaneously and using the elimination method,

Multiply equation 1 by 1 and equation 2 by 2

2x + 3y = 5.13

2x + 6y = 6.18

Subtracting,

-3y = -1.05

y = -1.05/-3= $0.35

Put y= 0.35 in equation, x + 2y = 3.09

x + 2(0.35)= 3.09

x + 0.7= 3.09

x = 3.09-0.7 = $ 2.39

So a bag of chip costs $2.39

5 0

2 years ago

A cicular pool with a radius of 12 meter if filled with water to a depth of 3 meters. what is the weight of water in the swimmin

Tcecarenko [31]

The weight of water in swimming pool is 13305600kg

5 0

2 years ago