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AlladinOne [14]
3 years ago
8

You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart

h with enough speed to make it to the moon. Some information that will help during this problem: mearth = 5.9742 x 1024 kg rearth = 6.3781 x 106 m mmoon = 7.36 x 1022 kg rmoon = 1.7374 x 106 m dearth to moon = 3.844 x 108 m (center to center) G = 6.67428 x 10-11 N-m2/kg2
Physics
1 answer:
hichkok12 [17]3 years ago
7 0

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}

now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}

so we will have

r = 3.46 \times 10^8 m

Now by energy conservation

-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}

-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

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False.

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What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?
fiasKO [112]
Momentum = mv
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v = momentum ÷ m
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4 0
3 years ago
Read 2 more answers
List the largest-aperture single telescope currently in use in each of the following bands of the electromagnetic spectrum: radi
tankabanditka [31]

Explanation:

Radio Telescope:

1. FAST (Five Hundred Meter Aperture Spherical Telescope), China is the largest single dish radio telescope in the world with a dish of diameter 500 meters. Although its construction is over but its not yet functional.

2. Arecibo Observatory, Puerto Rico is the largest single dish <em>operational</em> radio telescope having a single dish of diameter 305 meters..

X - ray Telescope: Chandra X ray observatory also known as Advanced X-ray Astrophysics Facility (AXAF) is the largest x-ray telescope with aperture of 1.2 meters. It can detect X-ray sources which are 100 times fainter in comparison to any previous telescope.

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2. Suppose that a parallel-plate capacitor has circular plates with radius R = 30 mm and a plate separation of d = 5.0 mm. Suppo
seropon [69]

Answer:

The maximum value of the induced magnetic field is 2.901\times10^{-13}\ T.

Explanation:

Given that,

Radius of plate = 30 mm

Separation = 5.0 mm

Frequency = 60 Hz

Suppose the maximum potential difference is 100 V and r= 130 mm.

We need to calculate the angular frequency

Using formula of angular frequency

\omega=2\pi f

Put the value into the formula

\omega=2\times\pi\times60

\omega=376.9\ rad/s

When r>R, the magnetic field is inversely proportional to the r.

We need to calculate the maximum value of the induced magnetic field that occurs at r = R

Using formula of magnetic filed

B_{max}=\dfrac{\mu_{0}\epsilon_{0}R^2\timesV_{max}\times\omega}{2rd}

Where, R = radius of plate

d = plate separation

V = voltage

Put the value into the formula

B_{max}=\dfrac{4\pi\times10^{-7}\times8.85\times10^{-12}\times(30\times10^{-3})^2\times100\times376.9}{2\times130\times10^{-3}\times5.0\times10^{-3}}

B_{max}=2.901\times10^{-13}\ T

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Learn more about comic in: brainly.com/question/1418309

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