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3 years ago

Explain why the gravitational acceleration of any object near earth is the same matter what was the mass of the object

1 answer:

5 0

It takes greater force to accelerate an object that has more mass. But the gravitational force between the Earth and an object is greater when the object hass more mass. It works out just right to make any object with any mass accelerate at the same rate.

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Aunt Jane weights 45 Newtons. What is her mass?

RUDIKE [14]

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

8 0

3 years ago

What is current of 12 ohm? help me pleasee

notsponge [240]

Answer:

the current of 12 ohm is 2Amps

4 0

2 years ago

A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of

nlexa [21]

Answer:

$a_c=1.44\ m/s^2$

Explanation:

<u>Centripetal Acceleration</u>

It's the acceleration that an object has when traveling on a circular path to take into consideration the constant change of velocity it must have in order to keep going in the circular path.

Being v the tangent speed, and r the radius of curvature of the circle, then the centripetal acceleration is given by

$\displaystyle a_c=\frac{v^2}{r}$

We can compute the value of v by using the distance and the time taken to travel:

$\displaystyle v=\frac{x}{t}=\frac{200\ m}{26.4\ s}$

$v=7.58\ m/s$

Now we calculate the centripetal acceleration

$\displaystyle a_c=\frac{7.58^2}{40}=1.44\ m/s^2$

$\boxed{a_c=1.44\ m/s^2}$

4 0

3 years ago

Cosmic Microwave Background radiation is one piece of supporting evidence for the Big Band Theory. Are these microwaves at the l

dolphi86 [110]

Answer:

it is long.

Explanation:

I know the answer but I don't know how to explain it

3 0

3 years ago

A satellite of mass m circles the earth a distance R from the center of the earth.If the radius of the earth is 6.0*10^6ms.calcu

Rom4ik [11]

(a) The height above the earth's surface of the parking orbit is determined from the difference between the orbital radius and earth's radius (h = r - R).

(b) Velocity of the satellite of the earth is determined with a formula given as (2π/T)r.

<h3>Height above the earth's surface </h3>

The height above the earth's surface is calculated using the following formula;

$T = \frac{2\pi r^{\frac{3}{2} }}{\sqrt{Gm} }$

where;

T is time period of the satellite
r is orbital radius

r = h + R

h = r - R

where;

h is height above the earth's surface
R is radius of earth

<h3>Velocity of the satellite</h3>

The velocity of the satellite is determined using the formula below;

v = ωr

v = (2π/T)r

Learn more about velocity of satellite here: brainly.com/question/22247460

#SPJ1

5 0

1 year ago