4 years ago

Which heavenly bodies are involved in causing the earths tides?

Physics

1 answer:

Elis [28]4 years ago

4 0

All of them except any planet means "Earth, Moon and the Sun"

so, option C is your answer.

Hope this helps!

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Select the correct answer.

TEA [102]

OA the speed will increase four times

4 0

3 years ago

Read 2 more answers

a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules

Bond [772]

Given:

Amount of heat produced = 100 kcal per hour

Let's find the rate of energy production in joules.

We know that:

1 calorie = 4.184 Joules

1 kcal = 4.184 Joules

To find the rate of energy production in Joules, we have:

$\begin{gathered} Rate=100\ast4.184 \\ \\ \text{Rate}=418.4\text{ KJ/hour} \end{gathered}$

Therefore, the rate of energy production in joules is 418.4 kJ/h which is equivalent to 418400 Joules

ANSWER:

418.4 kJ/h

6 0

1 year ago

You do 200 joules of work against gravity when lifting your backpack up a flight of stairs that is 4 meters tall. What is the we

kotegsom [21]

Answer:

Correct answer: F = 50 N weight of backpack

Explanation:

Given:

W = 200 J work against gravity

h = 4 m

F = m g = ?

g = 10 m/s²

The work done is a measure of change in this case of potential energy

W = Δ Ep = m g h = F · h ⇒ F = W / h =

F = W / h = 200 / 4 = 50 N

F = 50 N

God is with you!!!

8 0

4 years ago

What is the sound intensity of a whisper at a distance of 2.0 m, in W/m²? What is the corresponding sound intensity level in dB?

Rufina [12.5K]

To solve this problem we apply the concepts related to the Intensity, which is defined as the Power given by the object on unit area. Mathematically this is,

$I = \frac{P}{A}$

Where,

I = Intensity

P = Power

A = Area

Considering that a whisper is around to $1*10^{-10}W$ , then we have that

$I = \frac{1*10^{-10}}{2^2}$

$I = 2.5*10^{-11} W/m^2$

Intensity level in

$\beta = 10log (\frac{I}{I_0})$

Where,

$I_0 =$ Threshold intensity level

$\beta = 10log (\frac{2.5*10^{-11}}{1*10^{-12}})$

$\beta = 14dB$

Therefore the corresponding sound intensity level is 14dB

4 0

3 years ago

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

NikAS [45]

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

Here,

v = 45m/s

t = 5s

d = v × t

Therefore,

d = 45 × 5

= 225m

6 0

3 years ago