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3 years ago

Which heavenly bodies are involved in causing the earths tides?

Physics

1 answer:

Elis [28]3 years ago

4 0

All of them except any planet means "Earth, Moon and the Sun"

so, option C is your answer.

Hope this helps!

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A ball of mass m is thrown straight upward from ground level at speed v0. At the same instant, at a distance D above the ground,

Alla [95]

Answer:

Explanation:

Let the balls collide after time t .

distance covered by falling ball

s₁ = v₀ t + 1/2 g t²

distance covered by rising ball

s₂ = v₀ t - 1/2 g t²

Given ,

s₁ + s₂ = D

D = v₀ t + 1/2 g t² + v₀ t - 1/2 g t²

= 2v₀ t

t = D / 2v₀

s₂ = v₀ t - 1/2 g t²

= v₀ x D / 2v₀ - (1/2) x g x D² / 4v₀²

= D / 2 - gD² / 8 v₀²

6 0

2 years ago

Kathy 82 kg performer standing on a diving board at the carnival dive straight down into a small pool of water. Just before stri

mixas84 [53]

Solution :

Given weight of Kathy = 82 kg

Her speed before striking the water, $V_o$ = 5.50 m/s

Her speed after entering the water, $V_f$ = 1.1 m/s

Time = 1.65 s

Using equation of impulse,

$dP = F \times dT$

Here, F = the force ,

dT = time interval over which the force is applied for

= 1.65 s

dP = change in momentum

dP = m x dV

$= m \times [V_f - V_o]$

= 82 x (1.1 - 5.5)

= -360 kg

∴ the net force acting will be

$F=\frac{dP}{dT}$

$F=\frac{-360}{1.65}$

= 218 N

8 0

2 years ago

Along the remote Racetrack Playa in Death valley, California, stones sometimes gouge out prominent trails in the desert floor, a

REY [17]

Answer:

F = 196 N

Explanation:

For this exercise we will use Newton's second law, we define a reference system with the x axis in the direction of movement of the stones and the y axis vertically

Y axis

N- W = 0

N = mg

X axis

F -fr = ma

In this case, they ask us for the force to keep moving, so the stones go at constant speed, which implies that the acceleration is zero.

F- fr = 0

F = fr

the friction force has the equation

fr = μ N

fr = μ mg

we substitute

F = μ mg

let's calculate

F = 0.80 9.8 25

F = 196 N

8 0

3 years ago

A record turntable rotates through 5.0 rad in 2.8 s as it is accelerated uniformly from rest. What is the angular velocity at th

Usimov [2.4K]

Answer:

$\omega_f = 3.584\ rad/s$

Explanation:

given,

turntable rotate to, θ = 5 rad

time, t = 2.8 s

initial angular speed = 0 rad/s

final angular speed = ?

now, using equation of rotational motion

$\theta = \omega_i t + \dfrac{1}{2}\alpha t^2$

$5 = 0+ \dfrac{1}{2}\alpha\times 2.8^2$

$\alpha= \dfrac{10}{2.8^2}$

α = 1.28 rad/s²

now, calculation of angular velocity

$\omega_f = \omega_i + \alpha t$

$\omega_f =0 +1.28\times 2.8$

$\omega_f = 3.584\ rad/s$

hence, the angular velocity at the end is equal to 3.584 rad/s

4 0

3 years ago

20 POINTSSS!!!!!!!!

Soloha48 [4]

Answer: A
Hope this help you!!

7 0

3 years ago