A magnetic field is made by electric currents that is induced from opposite terminals of charges. When a current-carrying conductor is placed in a magnetic field, the electrons move to a certain direction. The guide used for this is Fleming's Left-Hand Rule as shown in the picture. It shows that the motion of the electron is in right angles or perpendicular to the force of the magnetic field. The resulting path of the direction of the electron will be in circular motion.This is the concept used in transformers where a voltage is induced from coils of currents. The electrons move in a helical or circular motion.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
Answer:
See the answer below
Explanation:
a. The volume in the first measuring cylinder reads 70
while that of the second reads 95
. Hence;
V1 = 70 
V2 = 95 
b. <u>An object will always displace its own volume in a liquid</u>. Hence:
Volume V of the rock sample = V2 - V1
= 95 - 70 = 25 
c. Mass of A = 102 g
Volume of A = 25 
<em>Density = mass/volume</em>
Hence, density of A = 102/25 = 4.08 g/
20N•m or 20J. Work is equal to force•distance, and 5N•4m is 20N•m, or J
41.5 is the answer that i got. hope this helps!