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denis-greek [22]
3 years ago
15

A piston in a gas supply pump has an

Physics
2 answers:
eimsori [14]3 years ago
6 0
<h2>Option A is the correct answer.</h2>

Explanation:

Pressure is the ratio of normal force to the area.

\texttt{Pressure = }\frac{\texttt{Normal force}}{\texttt{Area}}

Force = Pressure x Area

Area = 500 cm² = 0.05 m²

Pressure = 4000 Pa

Force = 0.05 x 4000 = 200 N

We know that

                Work done = Force x Displacement

                 W = F x d

                 Displacement, d = 30 cm = 0.3 m

                 W = 200 x 0.3 = 60 Joules.

Option A is the correct answer.

KonstantinChe [14]3 years ago
5 0

Answer:

A. 60 Joule

Explanation:

First find the force given the pressure and area.

F = AP

F = 500 cm² × (1 m / 100 cm)² × 4000 N/m²

F = 200 N

Now find the work:

W = Fd

W = 200 N × 30 cm × (1 m / 100 cm)

W = 60 J

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Does the same battery always deliver the same amount of flow to any circuit? Mention two observations of any circuits in this la
V125BC [204]

Answer:

Yes

Explanation:

Given that the battery is the same the PD ( potential difference ) in the circuit will also be the same likewise the flow of charge in the circuit,

Hence the same amount of charge flow is delivered to any circuit.

attached below are examples

6 0
3 years ago
Vertical Motion
harina [27]
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3 0
3 years ago
Somebody please help
suter [353]

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

a)

In the attached image we can find the free body diagram.

b)

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

F_{r}=275+275-310\\F_{r}=240[N]

c)

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

240=2250*a\\a=0.1067[m/s^{2} ]

5 0
3 years ago
Calculate the force between charges of 5.0 x 10^-8 c and 1.0 x 10^-7 if they are 5.0 feet apart
weqwewe [10]

Answer:

F = 19.375 x 10^-6  N

Explanation:

This problem can be solved by applying Coulomb's Law, which lets us determine the force between two electrically charged particles.

It is defined as

F = (ke * q1 * q2)/ r^2

Where,

ke =  is Coulomb's constant ≈ 9×10^9 N⋅m^2⋅C^−2

q1 = 5.0 x 10^-8 C

q2 = 1.0 x 10^-7 C

r = 5 ft = 1,524 m

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F  = (9×10^9 N⋅m^2⋅C^−2)*(5.0 x 10^-8 C)*(1.0 x 10^-7 C)/ ((1,524 m)^2)

F = 19.375 x 10^-6  N

6 0
3 years ago
what is the cost to run a single 100 w light bulb for 30 days if the electric company charges $0.18 for every KW-hr?​
xxTIMURxx [149]

Explanation:

power of the bulb = 100w=0.1kw

power consumption when the bulb is used for 30 days ( 30 *24 = 720 hours) =0.1*720=72kwh

cost to run the bulb for 30 days = 72*0.18

= $12.96

Answer is $12.96..................

8 0
3 years ago
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