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Nata [24]
3 years ago
12

A dog chases a skateboarder travelling at 10.4\,\dfrac{\text{m}}{\text{s}}10.4 sm ​ 10, point, 4, start fraction, start text, m,

end text, divided by, start text, s, end text, end fraction. The skateboarder speeds up with a constant acceleration for 39\,\text{m}39m39, start text, m, end text over 3.3\,\text{s}3.3s3, point, 3, start text, s, end text. We want to find the acceleration of the skateboarder over the 3.3\,\text{s}3.3s3, point, 3, start text, s, end text time interval
Physics
1 answer:
ehidna [41]3 years ago
7 0

Answer:Δx=v0t + 1/2 at 2

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3 years ago
ILL MARK AS BRAINLIEST AND THANK YOU FROM THE GODS, PLEASE HELP
Nataly_w [17]

Answer:

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Explanation:

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4 0
3 years ago
I’m still lost on this please help me on this I know it’s not D I got it wrong
RSB [31]

Before you even look at the questions, look over the graph, so you know what kind of information is there.

The x-axis is "time".  OK.  You know that as the graph moves from left to right, it shows what's happening as time goes on.

The y-axis is "speed" of something.  OK.  When the graph is high, the thing is moving fast.  When the graph is low, the thing is moving slow.  When the graph slopes up, the thing is gaining speed.  When the graph slopes down, the thing is slowing down.  When the graph is flat, the speed isn't changing, so the thing is moving at a constant speed.

NOW you can look at the questions.

OMG !  It's only ONE question:  What's happening from 'c' to 'd' ?  Well I don't know.  Perhaps we can figure it out if we LOOK AT THE GRAPH !

-- Between c and d, the graph is flat.  The speed is not changing.  It's the same speed at d as it was back at c .

What speed is it ?

-- Look back at the y-axis.  The speed at the height of c and d is 'zero' .

-- The 2nd and 4th choices are both correct.  From c to d, <em>the speed is constant</em>.  The constant speed is zero.  <em>The car is not moving</em>.

5 0
3 years ago
The Earth's atmosphere is opaque to the
Firdavs [7]
All of the above is correct
4 0
3 years ago
Two hockey pucks, labeled A and B, are initially at rest on asmooth ice surface and are separated by a distance of18.0 m. Simult
zlopas [31]

Answer:

8.505 m

Explanation:

Let V1 and V2 be velocities of puck A and B respectively

Since A and B move in the same direction, so the relative velocity will be V1+V2=3.5+3.9=7.4m/s

Or

Vr=7.4 m/s

Distance=S= 18 m

Time =t=?

S=Vr×t

==> t=S/Vr

==> t= 18/7.4=2.43 sec

At this time both will strike together

<em><u>Distance by puck A</u></em>

<em>V1=3.5 m/s</em>

Time=t= 2.43 sec

Distance covered=d=?

d=V1×t=3.5×2.43=8.505 m

So, puck A will cover 8.505 meters before collision

6 0
3 years ago
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