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iogann1982 [59]
3 years ago
13

The average rate of disappearance of ozone in the reaction is

Physics
1 answer:
olasank [31]3 years ago
7 0

Answer:

1.3 x 10^(-2) atm/s

Explanation:

It follows the stoichiometry. For every mole of O3 that disappears, 1.5 moles (that is, 3/2) of O2 appears:

1.5 * 0.009 atm/s = 0.0135 atm/sec; the answer is 1.3 x 10^(-2) atm/s

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Answer: I am pretty sure that you should pick radio waves.

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The best I could do.

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3 years ago
You are attempting to row across a stream in your rowboat. Your paddling speed relative to still water is 3.0 m/s (i.e., if you
Nataliya [291]

Answer:

Please check the attached file for the diagram

Explanation:

The velocity of the of the rowboat V_{tot}  through the river is the resultant velocity. It is obtained taking a vector sum of the velocity in still water and the velocity of the river.

There are several ways to take this vector sum, but the question makes it simple for us to use Pythagoras's theorem because the East and North directions are perpendicular to each other.

Hence;

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3 years ago
What is something that has a lot of thermal energy?
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Read 2 more answers
An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t
Liono4ka [1.6K]

(a) 5.69 N/C, vertically downward

We can calculate the acceleration of the electron by using the SUVAT equation:

d=ut+\frac{1}{2}at^2

where

d = 4.50 m is the distance travelled by the electron

u = 0 is the initial velocity of the electron

t=3.00 \mu s = 3.0 \cdot 10^{-6} s is the time of travelling

a is the acceleration

Solving for a,

a=\frac{2d}{t^2}=\frac{2(4.50)}{(3.0\cdot 10^{-6})^2}=1.0\cdot 10^{12} m/s^2

Given the mass of the electron,

m=9.11\cdot 10^{-31} kg

We can find the electric force acting on the electron:

F=ma=(9.11\cdot 10^{-31})(1.0\cdot 10^{12})=9.11\cdot 10^{-19}N

And the electric force can be written as

F=qE

where

q=-1.6\cdot 10^{-19}C is the charge of the electron

E is the magnitude of the electric field

Solving for E,

E=\frac{F}{q}=\frac{9.11\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=-5.69 N/C

The negative sign means that the direction of the electric field is opposite to the direction of the force (because the charge is negative): since the force has same direction of the acceleration (vertically upward), the electric field must point vertically downward.

(b) Yes

We can answer the question by calculating the magnitude of the gravitational force acting on the electron, to check if it is relevant or not. The gravitational force on the electron is:

F=mg

where

m=9.11\cdot 10^{-31} kg is the mass of the electron

g=9.81 m/s^2 is the acceleration due to gravity

Substituting,

F=(9.11\cdot 10^{-31})(9.81)=8.93\cdot 10^{-30}N

We see that the gravitational force is basically negligible compared to the electric force calculated in part (a), therefore we can say it is justified to ignore the effect of gravity in the problem.

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A cert is searching for survivors in a building after an electrical storm. the door to one of the rooms that the team needs to s
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