What is the label for coefficient of friction

Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp

shutvik [7]

Answer: 500 Watts

Explanation:

Power $P$ is the speed with which work $W$ is done. Its unit is Watts ( $W$ ), being $1 W=\frac{1 Joule}{1 s}$ .

Power is mathematically expressed as:

$P=\frac{W}{t}$ (1)

Where $t$ is the time during which work $W$ is performed.

On the other hand, the Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path. It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter ( $1J=(1N)(1m)=Nm$ ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

$W=(F)(d)$ (2)

In this case, we have the following data:

$F=500 N$

$d=10 m$

$t=10 s$

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

$W=(500 N)(10 m)$ (3)

$W=5000 J$ (4)

Substituting (4) in (1):

$P=\frac{5000 J}{10 s}$ (5)

Finally:

$P=500 W$

3 0

3 years ago

The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of t

EastWind [94]

Answer:

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

$Ay = By = \frac{w * 6}{2} = 3w$

$P_c_r = 3w * F.S = 3w * 2.0 = 6w$

$I = \frac{\pi}{64} (0.05)^4 = 3.067*10^-^7$

To find the maximum intensity, w, let's take the Pcr formula, we have:

$P_c_r = \frac{\pi^2 E I}{(KL)^2}$

Let's take k = 1

$E = 200*10^9$

Substituting figures, we have:

$6w = \frac{\pi^2 * 200*10^9 * 3.067*10^-^7}{(1 * 3)^2}$

Solving for w, we have:

$w = \frac{67266.84}{6}$

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

$\sigma _c_r = \frac{w}{A}$

$\sigma _c_r = \frac{11.211}{\pi (0.05)^2} = 1.4 MPA < \sigma y$ . This means it is safe

The maximum intensity w = 11.211KN/m

3 0

3 years ago

4. A car accelerates uniformly from rest at 3.2 m/s^.

Oksi-84 [34.3K]

Answer:

A

Explanation:

7 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

nalin [4]

Answer:

The maximum volume is 1417.87 $inch^3$

Explanation:

<u>Optimization Using Derivatives</u>

We have a 24x30 inch piece of metal and we need to make a rectangular box by cutting a square from each corner of the piece and bending up the sides. The width of the piece is 24 inches and its length is 30 inches

When we cut a square of each corner of side x, the base of the box (after bending up the sides) will be (24-2x) and (30-2x), width and length respectively. The volume of the box is

$V=(24-2x)(30-2x)x$

Operating

$V=4x^3-108x^2+720x$

To find the maximum value of V, we compute the first derivative and equate it to zero

$V'=12x^2-216x+720=0$

Simplifying by 12

$x^2-18x+60=0$

Completing squares

$x^2-18x+81-81+60=0$

$(x-9)^2=21$

We have two values for x

$x=9+\sqrt{21}=13.58\ inch$

$x=9-\sqrt{21}=4.42\ inch$

The first value is not feasible because it will produce a negative width (24-2(13.58))=-6.16

We'll keep only the solution

$x=4.42\ inch$

The width is

$w=(24-2(4.42))=15.16\ inch$

The length is

$l=(30-2(4.42))=21.16\ inch$

And the height

$x=4.42\ inch$

The maximum volume is

$V=(15.16)(21.16)(4.42)=1417.87\ inch^3$

4 0

3 years ago

According to Ohm's law, which is stated as I = V + R, which two sentences are true?

Novay_Z [31]

So, If the resistance decreases, then the current increases. Assume voltage is constant.

If the voltage increases, then the current increases. Assume resistance is constant.

Explanation:

According to the ohm's law; I = V/R;

If the resistance decreases the current increases assuming that the voltage is constant
if the voltage increases, then the current increases assuming that the resistance is constant.

Based on Ohm's law, we know that the current through a metallic conductor is directly proportional to the voltage across the ends.

From the relationship;

I = $\frac{V}{R}$

we see that V = IR

These equations affirms that

If the resistance decreases the current increases assuming that the voltage is constant based on the second equation

if the voltage increases, then the current increases assuming that the resistance is constant based on the first equation.

learn more:

Electric circuit brainly.com/question/10421964

#learnwithBrainly

7 0

3 years ago