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NeTakaya
2 years ago
5

What is the label for coefficient of friction

Physics
1 answer:
Tomtit [17]2 years ago
7 0
Force]/[force] = Newon/Newton = 1
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The speed of light in a vacuum is 3 x 108 miles/hour. true/false?
GarryVolchara [31]
I'm guessing they rounded because it is technically 2.998 X 108 miles/hour

so I would go with true!
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Which scientific law states the relationship between an object's mass, acceleration, and amount of force acting on it? (3 points
Kisachek [45]

Answer:

4.Newton's second law of motion

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HELP PLEASE!!!
Leya [2.2K]

For the first one 320

second

1200W

Data

R = 12 Ω ∆V = 120V I =? P =?

Solution:

According to Ohm’s law,

∆V = I R

I = ∆V / R  

= 120 / 12  

= 10 A

Power P = I ∆V  

= 10 x 120  

= 1200 W

Third

∆V = 120 V P = 60 W I =? R =?

Use the formula, P = I ∆V

I = P / ∆V = 60 / 120 = 0.5 A

∆V = I R

R = ∆V / I = 120 / 0.5 = 240 Ω

3 0
3 years ago
A 1,100 kg car is traveling initially 20 m/s when the brakes are applied. The brakes apply a constant force while bringing the c
Natalka [10]

Answer:

Work done = -220,000 Joules.

Explanation:

<u>Given the following data;</u>

Mass = 1100kg

Initial velocity = 20m/s

To find workdone, we would calculate the kinetic energy possessed by the car.

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where,

  • K.E represents kinetic energy measured in Joules.
  • M represents mass measured in kilograms.
  • V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

K.E = \frac{1}{2}*1100*20^{2}

K.E = 550*400

K.E = 220,000J

Therefore, the workdone to bring the car to rest would be -220,000 Joules because the braking force is working to oppose the motion of the car.

4 0
2 years ago
17.
avanturin [10]

Answer:

Gamma rays

Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.

Explanation:

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2 years ago
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