Answer:
I have not dealt with slope for a while but if its in the form y=mx+b then the x is the slope so it would be -3/4x and b is the y intercept. the y in the cords is -6
Step-by-step explanation:
y= -3/4x -6
1. For multiplication and division), we first compare the number of significant figure (let's call it SF later in the problem) that the factors have. The product will have the least numbers between them. So, for the case of 11.55 x 2.5, 11.55 has 4 SF while 2.5 has 2. So we choose the smallest which is 2 for this case. Hence, the answer is B.
2. Using the same rules as mentioned in Item 1, we first compare the number of SF in the numbers give. 975.0321 has 7 SF while 0.0003 has 1 (all zeroes not following a counting number are not significant). We now solve for the quotient and round it off to 1 SF.
(975.0321/0.0003) = 3250107. Rounding it off, we have 3000000 or 3 x 10⁶. Thus, the answer is D.
3. The rules for multiplication still apply even for more than two factors. So, let's first take note of the SF present in each factor as shown below.
0.00147 = 3 SF
8.314 = 4 SF
7.100 = 4 SF (zeroes after a counting number in the decimal place are considered significant)
From this, we can see that the product must round off to 3 SF. Multiplying the three numbers, we have
0.00147 x 8.314 x 7.100 = 0.086773218
So, the product rounded off to 3 SF is 0.0868 or 8.68 x 10⁻². So, the answer must be C<span>.
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<span>x^7+14x^6y+84x^5y^2+280x^4y^3+560x^3y^4+672x^2y^5+448xy^6+128y^7
answer D
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A because you have to make 16/32 into 1/2, and 4/16 is not a half.
so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well, you know, if we end up with a 0 at the denominator, like
then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.
so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".
