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N76 [4]
3 years ago
13

Write a numerical expression with exponents to describe the sum of 3x3x3x3 and 36

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

3^{4} and 6^{2}

Step-by-step explanation:

The given expression are 3 \times 3 \times 3 \times 3 and 36.

To write the first one as exponents, we just set the number 3 as a base and the exponent as number 4, because the repeating number is 3 and the number of repetitions is 4.

3 \times 3 \times 3 \times 3=3^{4}

Now, to express the number 36 as exponent, we just need to find a number which power results in 36, and that number is 6, which multiplied twice by itself gives 36 as result.

36 = 6^{2}

grandymaker [24]3 years ago
4 0

Answer:

3^3 and 36^1

Step-by-step explanation:

3x3x3x3 is multiplying that 4 times so it is to the power of 4

36 is just once so it is to the power of one

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Alexeev081 [22]

Step-by-step explanation:

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3 years ago
Please answer this question now
xz_007 [3.2K]

Answer:

397.7 m²

Step-by-step Explanation:

Step 1: find m < W

W = 180 - (33+113) (sum of ∆)

W = 34°

Step 2: find side UV using the law of sines

\frac{UV}{sin(W)} = \frac{VW}{sin(U)}

\frac{UV}{sin(34)} = \frac{29}{sin(33)}

Multiply both sides by sin(34)

\frac{UV}{sin(34)}*sin(34) = \frac{29}{sin(33)}*sin(34)

UV = \frac{29*sin(34)}{sin(33)}

UV = 29.8 m (approximated)

Step 3: find the area using the formula, ½*UV*VW*sin(V)

area = ½*29.8*29*sin(113)

Area = 397.7 m² (rounded to the nearest tenth.

7 0
3 years ago
The length of a rectangle is twice its width.
goldfiish [28.3K]
P = 2l + 2w
l = 2w

48 = 2(2w) + 2w
48 = 4w + 2w
48 = 6w
8 = w

l = 2w
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48 = 2(16) + 2(8)
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Answer:
length = 16
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8 0
3 years ago
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Solve for x ~<br><img src="https://tex.z-dn.net/?f=4x%20-%2016%20%3D%2064" id="TexFormula1" title="4x - 16 = 64" alt="4x - 16 =
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\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve for x ~

\qquad \sf  \dashrightarrow \:4x - 16 = 64

\qquad \sf  \dashrightarrow \:4(x - 4) = 64

\qquad \sf  \dashrightarrow \:(x - 4) = 64 \div 4

\qquad \sf  \dashrightarrow \:x - 4 = 16

\qquad \sf  \dashrightarrow \:x  = 16 + 4

\qquad \sf  \dashrightarrow \:x  =20

6 0
2 years ago
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Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}
user100 [1]

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}

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3 years ago
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