Answer: 0.424 J/g°C
Explanation:
For this problem, we would have to manipulate the equaiton for heat, q=mCT. Specific heat is the C in the equation. Since we are looking for specific heat, we manipulate the equation so that it says C=.

*I didn't know how to type in delta so I just wrote the word delta, but pretend you see a Δ.
Now that we have our equation, we can plug in our values and solve.

*Please ignore the capital A in the equation. It pops up every time I type in the ° sign.

The answer would be Hydrosphere
Hey there !
Solution :
Moles of solution = 5.0
Volume of solution = 10 L
Therefore :
M = n / V
M = 5.0 / 10
= 0.5 M
Answer:
16.54 mL
Explanation:
From the question;
- Density of mercury of 13.6 g/mL
- Mass of the mercury metal is 225 g
We are needed to determine the volume of the mercury metal;
We need to know that;
- Density is given by dividing the mass of a substance by its volume.
That is;
Density = Mass ÷ Volume
Rearranging the formula;
Volume = Mass ÷ Density
Therefore;
Volume = 225 g ÷ 13.6 g/mL
= 16.54 mL
Thus, the volume of the mercury needed is 16.54 mL