Answer:
3 electrons
Explanation:
The elements of group 5A of the periodic table are the following:
nitrogen, sodium, arsenic, antimony and bismuth.
To determine the amount of electrons in the last energy level we need to know the electronic configuration of each element.
Electronic configuration
N: [He] 2s2 2p3
P: 1s2 2s2 2p6 3s2 3p3
As: [Ar] 3d10 4s2 4p3
Sb: [Kr] 4d10 5s2 5p3
Bi: [Xe] 4f14 5d10 6s2 6p3
As we can see they all have 3 electrons in their last energy level
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It is b because I need to answer my first question
Frequency can effect how tall or how long these Wavelengths are and their strength, therefore how "frequently" they will complete a wave-cycle.
The transition metals are a group of metals that are found in the middle of the periodic table. ... They are also harder than the post transition metals. They make colorful chemical compounds with other elements. Most of them have more than one oxidation state.
The correct option is (b)
NaNH2 is an effective base. It can be a good nucleophile in the few situations where its strong basicity does not have negative side effects. It is employed in elimination reactions as well as the deprotonation of weak acids.Alkynes, alcohols, and a variety of other functional groups with acidic protons, such as esters and ketones, will all be deprotonated by NaNH2, a powerful base.Alkynes are deprotonated with NaNH2 to produce what are known as "acetylide" ions. These ions are powerful nucleophiles that can react with alkyl halides to create carbon-carbon bonds and add to carbonyls in an addition reaction.Acid/base and nucleophilic substitution are the two types of reactions.Using the right base, terminal alkynes can be deprotonated to produce a carbanion.A good C is the acetylide carbanion.The acetylide carbanion can undergo nucleophilic substitution reactions because it is a potent C nucleophile. (often SN2) with 1 or 2 alkyl halides with electrophilic C to create an internal alkyne (Cl, Br, or I).Elimination is more likely to occur with 3-alkyl halides.It is possible to swap either one or both of the terminal H atoms in ethylene (acetylene) to create monosubstituted (R-C-C-H) and symmetrical (R = R') or unsymmetrical (R not equal to R') disubstituted alkynes (R-C-C-R').
Learn more about NANH2 here :-
brainly.com/question/12601787
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