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sukhopar [10]
3 years ago
5

Which element is least likely to react with other elements

Chemistry
2 answers:
KIM [24]3 years ago
5 0
The least reactive elements are in the right-most column of the periodic table, and are known as the noble gases. Examples are Helium, Xeon, Neon, Argon, etc.
Anni [7]3 years ago
3 0
Nobles gases, since they all have 8 e- on their last layer of electrons.
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Boyle's Law represents the relationship of volume as pressure changes. The constants of Boyle's Law are:
Aleksandr [31]

Answer:

d. Temperature and number of molecules of gas  

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the <em>variables</em>.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are <em>wrong</em>, because pressure is a variable.

b is <em>wrong</em>, because volume is a variable.

5 0
3 years ago
Provide the structure of the cyanohydrin that results when cyclopentanone reacts with hcn.
dusya [7]

Answer:

All the related answers are attached image formats...Regards

5 0
3 years ago
The salt formed by the reaction of the weak acid hydrocyanic acid, HCN, with the strong base potassium hydroxide is
iogann1982 [59]

Answer:

2.28 × 10^-3 mol/L

Explanation:

The equation for the equilibrium is

CN^- + H2O ⇌ HCN + OH^-

                    Ka = 4.9 × 10^-10

               KaKb = Kw

4.9 × 10^-10 Kb = 1.00 × 10^-14

                   Kb = (1.00 × 10^-14)/(4.9 × 10^-10) = 2.05 × 10^-5

Now, we can set up an ICE table

                     CN^- + H2O ⇌ HCN + OH^-

I/(mol/L)      0.255                     0         0

C/(mol/L)       -x                        +x        +x

E/(mol/L)  0.255 - x                   x         x

Ka = x^2/(0.255 - x) = 2.05 × 10^-5

Check for negligibility

0.255/(2.05 × 10^-5) = 12 000 > 400. ∴ x ≪ 0.255

    x^2 = 0.255(2.05 × 10^-5) = 5.20 × 10^-6

        x = sqrt(5.20 × 10^-6)    = 2.28 × 10^-3

[OH^-] = x mol/L                     = 2.28 × 10^-3 mol/L

5 0
3 years ago
128g of sulphur are burned in excess oxygen. What mass of sulphur dioxide forms? S + O2 --&gt; SO2 *
Rasek [7]

Mass of Sulphur dioxide : 256 g

<h3>Further explanation</h3>

Given

Reaction

S + O2 --> SO2 *

Required

Mass of Sulphur dioxide

Solution

mol of Sulphur (Ar=32 g/mol) :

mol = mass : Ar

mol = 128 : 32

mol = 4

From the equation, mol ratio S : SO2 = 1 : 1, so mol SO2 = 4

Mass of SO2 :

mass = mol x MW SO2

mass = 4 x 64

mass = 256 g

5 0
3 years ago
Could you determine the half life of an isotope by looking at 1 atom? Explain why or why not.
Bezzdna [24]

Answer:

Hope this helps u!!

Explanation:

A useful application of half-lives is radioactive dating. This has to do with figuring out the age of ancient things. If you could watch a single atom of a radioactive isotope, U-238, for example, you wouldn't be able to predict when that particular atom might decay. :) :)

Mark as Brainliest plz!

3 0
3 years ago
Read 2 more answers
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