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Lorico [155]
3 years ago
10

The Loch Ness monster is a sea serpent that is thought to live in a lake in

Chemistry
2 answers:
Ray Of Light [21]3 years ago
6 0

<u>Answer:</u>

Scotland

The loch ness monster is Scottish

:)

Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

Scotland

Explanation:

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Sentences with biocycle
dusya [7]
<span>Associating the need of surgeon in practice , we write a software of human body biocycle law . this software can provide a science reliance in the time selection of surgical operation plan to the main surgeon
(just an example^)</span>
4 0
3 years ago
The total number of electrons in the outer shell of a sodium atom is?<br>A. 1<br>B.2<br>C.8<br>D.18​
mrs_skeptik [129]

Answer:

1

Explanation:

outershell atoms of an element are also known as valency of that element

so the valency and number of elctron in the outershell of a sodium atom is +1.

hope this will help

mark me as brilliant

7 0
3 years ago
Which of the following samples contains the greatest number of atoms?
mart [117]

Answer:

C. 11 moles of N2O

Explanation:

A. CO2 exists as a molecular compound. The number of atoms present = 1 atom of Carbon and 2 atoms oxygen = 3 atoms * 9 = 18 atoms

B. Xe exists as an atom. Number of atoms present = 10 * 1 atom = 10 atoms

C. N20 contains 3 atoms; 2 atoms of Nitrogen and 1 atom of oxygen.

Number of atoms present = 3 * 11 = 33 atoms

D. CO contains 2 atoms, 1 each of carbon and oxygen.

Number of atoms present = 12 * 2 = 24 atoms

7 0
3 years ago
True or False: Rubbing a balloon on your head for a longer amount of time will increase the attractive force of the balloon.​
Andreyy89

Answer:

no

Explanation:

4 0
3 years ago
5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

5 0
3 years ago
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