The answer to your problem is The flow wire is diverted and comes to 12.06
Answer:
1.176
Explanation:
When the bullets impact the mass they become embedded on it, it is a plastic collision, therefore momentum is conserved.
v2 * (M + mb) = v1 * mb
Where
v1: muzzle velocity of the bullet
M: mass of the bob
mb: mass of the bullet
v2: mass of the bob with the bullet after being hit
v2 = v1 * mb / (M + mb)
Upon being impacted the bob will acquire speed v2, this implies a kinetic energy. The bob will then move and raise a height h. Upon acheiving the maximum height it will have a speed of zero. At that point all kinetic energy will be converted into potential energy.
Ek = 1/2 (M + mb) * v2^2
Ep = (M + mb) * g * h
Ek = Ep
1/2 (M + mb) * v2^2 = (M + mb) * g * h
1/2 * (v1 * mb / (M + mb))^2 = g * h
1/2 * v1^2 * mb^2 / (M + mb)^2 = g * h
v1^2 = g *h * (M+ mb)^2 / (1/2 * mb^2)
![v2 = \sqrt{\frac{g *h * (M+ mb)^2}{\frac{1}{2} * mb^2}}](https://tex.z-dn.net/?f=v2%20%3D%20%5Csqrt%7B%5Cfrac%7Bg%20%2Ah%20%2A%20%28M%2B%20mb%29%5E2%7D%7B%5Cfrac%7B1%7D%7B2%7D%20%2A%20mb%5E2%7D%7D)
The height h that it reaches is related to the length L of the pendulum arm and the angle it forms with the vertical.
h = L * (1 - cos(a))
![v2 = \sqrt{\frac{g * L * (1 - cos(a)) * (M+ mb)^2}{\frac{1}{2} * mb^2}}](https://tex.z-dn.net/?f=v2%20%3D%20%5Csqrt%7B%5Cfrac%7Bg%20%2A%20L%20%2A%20%281%20-%20cos%28a%29%29%20%2A%20%28M%2B%20mb%29%5E2%7D%7B%5Cfrac%7B1%7D%7B2%7D%20%2A%20mb%5E2%7D%7D)
For the 9 mm:
![v2 = \sqrt{\frac{9.81 * L * (1 - cos(4.3)) * (10+ 0.006)^2}{\frac{1}{2} * 0.006^2}} = \sqrt{L} * 391](https://tex.z-dn.net/?f=v2%20%3D%20%5Csqrt%7B%5Cfrac%7B9.81%20%2A%20L%20%2A%20%281%20-%20cos%284.3%29%29%20%2A%20%2810%2B%200.006%29%5E2%7D%7B%5Cfrac%7B1%7D%7B2%7D%20%2A%200.006%5E2%7D%7D%20%3D%20%5Csqrt%7BL%7D%20%2A%20391)
For the 0.44 caliber:
![v2 = \sqrt{\frac{9.81 * L * (1 - cos(10.1)) * (10+ 0.012)^2}{\frac{1}{2} * 0.012^2}} = \sqrt{L} * 460](https://tex.z-dn.net/?f=v2%20%3D%20%5Csqrt%7B%5Cfrac%7B9.81%20%2A%20L%20%2A%20%281%20-%20cos%2810.1%29%29%20%2A%20%2810%2B%200.012%29%5E2%7D%7B%5Cfrac%7B1%7D%7B2%7D%20%2A%200.012%5E2%7D%7D%20%3D%20%5Csqrt%7BL%7D%20%2A%20460)
The ratio is 460 / 391 = 1.176
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Answer:
The complete question is:
Use a stem and leaf display to organize the following distribution of scores. Use six stems with each stem corresponding to a 10-point interval.
Scores: 16, 42, 53, 41, 69
34, 33, 40, 61, 23
53, 49, 55, 29, 10
44, 64, 51, 21, 39
36, 58, 60, 27, 47
14, 44, 38, 31, 56
The answer is:
The decimal point is 1 digit(s) to the right of the |
1 | 046
2 | 1379
3 | 134689
4 | 0124479
5 | 133568
6 | 0149
Explanation:
Answer:
The correct option is;
Terminate
Explanation:
Termination of the risk is equivalent to elimination of the risk by avoiding the activity that brings about the risk or by using a different process that does not include the risk observed in the previous process option
When the reward far outweigh the risk, it may be decided to terminate or eliminate the risk and miss the reward and also terminate the likelihood of the losses to be incurred.