Answer:
a) Δφ = 1.51 rad
, b) x = 21.17 m
Explanation:
This is an interference problem, as they indicate that the distance AP is on the x-axis the antennas must be on the y-axis, the phase difference is
Δr /λ = Δfi / 2π
Δfi = Δr /λ 2π
Δr = r₂-r₁
let's look the distances
r₁ = 57.0 m
We use Pythagoras' theorem for the other distance
r₂ = √ (x² + y²)
r₂ = √(57² + 9.3²)
r₂ = 57.75 m
The difference is
Δr = 57.75 - 57.0
Δr = 0.75 m
Let's look for the wavelength
c = λ f
λ = c / f
λ = 3 10⁸ / 96.0 10⁶
λ = 3.12 m
Let's calculate
Δφ = 0.75 / 3.12 2π
Δφ = 1.51 rad
b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains
Δr = (2n + 1) λ / 2
For the first interference n = 0
Δr = λ / 2
Δr = r₂ - r₁
We substitute the values
√ (x² + y²) - x = 3.12 / 2
Let's solve for distance x
√ (x² + y²) = 1.56 + x
x² + y² = (1.56 + x)²
x² + y² = 1.56² + 2 1.56 x + x²
y2 = 20.4336 +3.12 x
x = (y² -20.4336) /3.12
x = (9.3² -20.4336) /3.12
x = 21.17 m
This is the distance for the first minimum
Answer:
P(final) is 2.4 times P(initial).
Explanation:
Here we can assume that the cylinder did not break and it's volume and number of moles of gas present in the cylinder remains constant.
Given the temperature increases by a factor of 2.4. Let us assume that the initial temperature be 
and the final temperature be 
.
Given that 
Now we know the ideal gas equation is PV=nRT
here V=constant , n=constant , R=gas constant(which is constant).
Answer:
F = 183.153 N
Explanation:
given,
mass of the toothpick = 0.12 g = 0.00012 kg
initial velocity = 227 m/s
final velocity = 0 m/s
penetration depth = 16 mm = 0.016 m
using the equation of motion
v² - u² = 2 a s
0 - u² = 2 a s
- 221² = 2 × a × 0.016
a = 1526281.25 m/s²
Force is equal to
F = m a
= 0.00012 × 1526281.25
F = 183.153 N
Given that
Velocity of missile (v) = 20 m/s ,
Angle of missile (Θ) = 53°
Determine , Vertical component = v sin Θ
= 20 sin 53°
= 15.97 m/s
Because the information cant be out of the investigation
