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Darina [25.2K]
4 years ago
5

The collision between a hammer and a nail can be considered to be approximately elastic. Estimate the kinetic energy acquired by

a 13 g nail when it is struck by a 550 g hammer moving with an initial speed of 4.6 m/s.
Physics
1 answer:
AlekseyPX4 years ago
3 0
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What percentage of the intensity gets through both polarizers?
sp2606 [1]

Answer:

if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Explanation:

The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes

                I = I₀ cos² θ

therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

8 0
3 years ago
A truck drives with a constant linear speed v_iv i ​ v, start subscript, i, end subscript down a road with two curves. The first
Alex

Answer:

(C) Decreases by factor of 3

Explanation:

Centripetal acceleration is given by

a = \dfrac{v^2}{r}

where <em>v</em> is the linear velocity and <em>r</em> is the radius of the curve.

Let the centripetal acceleration on the curve of radius <em>R</em> be a_1.

Then

a_1 = \dfrac{v_i^2}{R}

Let the centripetal acceleration on the curve of radius 3<em>R</em> be a_2.

Then

a_2 = \dfrac{v_i^2}{3R} = \dfrac{1}{3}\dfrac{v_i^2}{R} = \dfrac{1}{3}a_1

Here, we see that the acceleration decreases by a factor of 3.

7 0
3 years ago
LSE
Zinaida [17]
B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?

v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²

c)displacement (s)=?
1st section of journey

v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters

2nd section of journey
a=0
t=7
u=8
s=?

s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters

56+55= 111 meters

(For graph x axis =time (sec) & y axis= velocity (m/s))

6 0
3 years ago
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn
Cerrena [4.2K]

Answer:

e. Not enough information to determine

Explanation:

This question is incomplete. Here is the complete question with my solution afterwards;

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)

a. The ladybug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The centripetal force acting on a rotating body or bugs can be written as,

F=mrw^2

m= mass of the corresponding bugs

r= corresponding radial distance of each bug

w= angular speed of the turntable

The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable

F ∝ mr

Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.

Option "e" is correct.

7 0
3 years ago
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mafiozo [28]
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6 0
3 years ago
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